urllib2.ProxyHandler

[rx]

I'm trying to hide my IP with the following code:

import urllib2
proxy=[urllib2.ProxyHandler({'http':'24.232.167.22:80'})]
opener=urllib2.build_opener(proxy)
f=opener.open('http://www.whatismyipaddress.com')
print f.read()

But that didn't work - my real IP showed up.

Then I made the following replacement:

proxy=[urllib2.ProxyHandler({'http':'24.232.167.22:80'})] ->
proxy=[urllib2.ProxyHandler({'http':'foo'})]

And got the exact same result.

What am I doing wrong ?
Do I need a name instead of 24.232.167.22 ? (but this IP and some others I
tried didn't have a name)

Thanks in advance....

[John J. Lee]

"rx" <do*******************@hotmail.com> writes:

I'm trying to hide my IP with the following code:

import urllib2
proxy=[urllib2.ProxyHandler({'http':'24.232.167.22:80'})]
opener=urllib2.build_opener(proxy)

build_opener takes *args, not a list:

import urllib2
handlers = [urllib2.ProxyHandler({'http':'24.232.167.22:80'})]
opener = urllib2.build_opener(*handlers)
or just:

import urllib2
proxy_handler = urllib2.ProxyHandler({'http':'24.232.167.22:80'})
opener = urllib2.build_opener(proxy_handler)
Also, IIRC 2.4 does not allow ports in proxy specification strings
(the values in the dict you pass to ProxyHandler's constructor), and
IIRC 2.5a1 ProxyHandler is broken (it's fixed in the SVN repository).
John