"dongdong" <do***********@hotmail.com> wrote in message
news:11**********************@u72g2000cwu.googlegr oups.com...
for example:
re.sub('<a( [^>]+)+\s?>[^<^>]*</a>','',' asd ga<a target="_blank"
href="http://www.sine.com" class="wordstyle"> asdgasdghae rha</a>')
I wish to get the return value "asd ga asdgasdghae rha",how do do?
I have a impression on "%" and "{number}",but forgot how to use them.
Well, here's the pyparsing rendition (two, actually). I hope it's easier to
follow then trying to pick apart the above regexp. Both
Download pyparsing at
http://pyparsing.sourceforge.net.
-- Paul
instr = """' asd ga<a target="_blank"
href="http://www.sine.com" class="wordstyle"> asdgasdghae rha</a>'"""
from pyparsing import makeHTMLTags,Suppress,MatchFirst
# makeHTMLTags returns a tuple of the start and end pattern for the given
tag
aStart,aEnd = makeHTMLTags("a")
# define a filter that will suppress the opening and closing tags
# this is easily extended to filter additional patterns, too
filter = Suppress(aStart) | Suppress(aEnd)
# invoke transformString using the filter
print filter.transformString(instr)
# or for the dense-code minded...
filter = MatchFirst( map( Suppress, makeHTMLTags("a") ) )
print filter.transformString(instr)
Prints:
' asd ga asdgasdghae rha'
' asd ga asdgasdghae rha'