Getting File Permissions

[Hari]

Hi,
For getting permissions of a file, the following script has been
suggested in the same group

import os, stat
st = os.stat(myfile)
mode = st[stat.ST_MODE]
print "mode is", octal(mode & 0777)

But while executing I am getting error message as follows

Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'octal' is not defined

Since I am new to python, can any one help me to solve this error?
A bunch of thanks in advance.

Hari

[Kent Johnson]

Hari wrote:

Hi,
For getting permissions of a file, the following script has been
suggested in the same group

import os, stat
st = os.stat(myfile)
mode = st[stat.ST_MODE]
print "mode is", octal(mode & 0777)

But while executing I am getting error message as follows

Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'octal' is not defined

The correct name is oct(). The docs on built-in functions are helpful here:
http://docs.python.org/lib/built-in-funcs.html

Kent

[Juho Schultz]

Hari wrote:

Hi,
For getting permissions of a file, the following script has been
suggested in the same group

import os, stat
st = os.stat(myfile)
mode = st[stat.ST_MODE]
print "mode is", octal(mode & 0777)

But while executing I am getting error message as follows

Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'octal' is not defined

Since I am new to python, can any one help me to solve this error?
A bunch of thanks in advance.

Hari

You can use "oct" instead of "octal".

[Tim Chase]

> Traceback (most recent call last):

File "<stdin>", line 1, in ?
NameError: name 'octal' is not defined

Since I am new to python, can any one help me to solve this error?

Looks like you just want the oct() function (not "octal()")

[x for x in dir(__builtins__) if x.lower().find("oct")

!= -1]
['oct']

The __builtins__ will tell you what functions python
supports natively, and you can query against this list for
patterns, as done above.

-tkc