Exceptions

[DavidPorterHolt]

Can anyone explain why the second print statement below (copied from
'Dive Into Python') generates a syntax error? As I understand
exceptions, the except block should handle the exception, and the
following print statement should execute normally.

try: fsock = open('/nothere')
except IOError:
print 'The file does not exist, exiting gracefully'
print 'This line will always print'
SyntaxError: invalid syntax

Any help will be much appreciated.

Thanks,
David Holt
Da*************@acm.org

[DavidPorterHolt]

Here's the same clip, but run in the command line interpreter. The
error gives a little more info.

try: .... fsock = open('/notthere')
.... except IOError:
.... print 'The file does not exist, exiting gracefully'
.... print 'This line will always print'
File "<stdin>", line 5
print 'This line will always print'
^
SyntaxError: invalid syntax

Thanks,
David Holt
Da*************@acm.org

[Paul McGuire]

"DavidPorterHolt" <Da*************@acm.org> wrote in message
news:11**********************@g47g2000cwa.googlegr oups.com...

Here's the same clip, but run in the command line interpreter. The
error gives a little more info.

try: ... fsock = open('/notthere')
... except IOError:
... print 'The file does not exist, exiting gracefully'
... print 'This line will always print'
File "<stdin>", line 5
print 'This line will always print'
^
SyntaxError: invalid syntax
Thanks,
David Holt
Da*************@acm.org

In the interpreter, after an indented group (such as your except IOError
block), you have to enter a blank line, THEN enter the 2nd print statement:

try: .... fsock = open('/notthere')
.... except IOError:
.... print 'The file does not exist, exiting gracefully'
....
The file does not exist, exiting gracefully print 'This line will always print' This line will always print

(Note the empty ellipsis, indicating a line with no more indention.)

-- Paul

[DavidPorterHolt]

That's good to know. Thanks.