kwargs keyword evaluation

[tzellman]

Ok, so here is my situation:

Let's assume I have a function that makes good use of the kwargs
parameter. It requires that there is a certain "format" for the kwargs
keywords. (I am using Django, btw). The format is like such:
"SOMEVAL__exact", etc., where SOMEVAL is some value that it parses from
the keyword.

Now, I want to call this function, specifying the kwargs. The problem
is that I want to dynamically set the kwargs. For example, I don't want
to hard code in the name like such:
function_call(name__exact="Tom")

I want to generate the keyword on the fly. So, I want to do this:
(assume someVar == 'name' for now)
keyword = someVar + "__exact"

The problem:
I need to know how to get it to use the VALUE of the keyword for the
keyword.
My thoughts:
(1) Maybe I can override the kwargs parameter by doing such:
function_call(kwargs={keyword:"Tom"})
*loud buzzer* Nope. (as expected)

(2) Maybe I can just pass it in:
function_call(keyword="Tom")
Nope! (as expected, it tries to use 'keyword' as the keyword)

What can I do?!?!?!?
I really don't want to have to hardcode a BUNCH of if statements.

Thanks in advance!

[Carsten Haese]

On Wed, 2006-02-15 at 11:40, tz******@gmail.com wrote:

Ok, so here is my situation:

Let's assume I have a function that makes good use of the kwargs
parameter. It requires that there is a certain "format" for the kwargs
keywords. (I am using Django, btw). The format is like such:
"SOMEVAL__exact", etc., where SOMEVAL is some value that it parses from
the keyword.

Now, I want to call this function, specifying the kwargs. The problem
is that I want to dynamically set the kwargs. For example, I don't want
to hard code in the name like such:
function_call(name__exact="Tom")

I want to generate the keyword on the fly. So, I want to do this:
(assume someVar == 'name' for now)
keyword = someVar + "__exact"

The problem:
I need to know how to get it to use the VALUE of the keyword for the
keyword.
My thoughts:
(1) Maybe I can override the kwargs parameter by doing such:
function_call(kwargs={keyword:"Tom"})
*loud buzzer* Nope. (as expected)

(2) Maybe I can just pass it in:
function_call(keyword="Tom")
Nope! (as expected, it tries to use 'keyword' as the keyword)

The correct answer is behind door number 3:

some_dict = {keyword: "Tom"}
function_call(**some_dict)

HTH,

Carsten.

[tzellman]

Well, I knew about the apply() function, but totally forgot to use it.
It worked.

Example:
apply(function_call, (), {keyword: "Tom"})

[Fredrik Lundh]

tz******@gmail.com wrote:

Let's assume I have a function that makes good use of the kwargs
parameter. It requires that there is a certain "format" for the kwargs
keywords. (I am using Django, btw). The format is like such:
"SOMEVAL__exact", etc., where SOMEVAL is some value that it parses from
the keyword.

Now, I want to call this function, specifying the kwargs. The problem
is that I want to dynamically set the kwargs. For example, I don't want
to hard code in the name like such:
function_call(name__exact="Tom")

I want to generate the keyword on the fly. So, I want to do this:
(assume someVar == 'name' for now)
keyword = someVar + "__exact"

The problem:
I need to know how to get it to use the VALUE of the keyword for the
keyword.

My thoughts:
(1) Maybe I can override the kwargs parameter by doing such:
function_call(kwargs={keyword:"Tom"})
*loud buzzer* Nope. (as expected)

function_call(**{keyword:"Tom"})

</F>

[tzellman]

Thanks. That also worked. I will use that, since apply() is deprecated
as of 2.3.

Thanks!
-Tom