How to create a script that list itself ?

[Patrick Allaire]

How to create a script that list itself ?

I would like to know, where is the script's code is stored once we
start it. I know I can achieve that, using files :

print file('myscript.py','rb').read()

But is there a way / a variable that contains the current file in
memory ?

Thanks.

Xaqc

[Grant Edwards]

On 2006-01-09, Patrick Allaire <pa******@gmail.com> wrote:

How to create a script that list itself ?
This is probably about as close as you're going to get:

import sys
pring open(sys.argv[0],'r').read()

And that isn't 100% reliable.
I would like to know, where is the script's code is stored once we
start it.
It isn't. At least none of the implimentations I know of have
the script's source code in memory. The PVM or JVM bytecodes
to which the program has been compiled are in memory somewhere,
and there _may_ be some trick you can use to get at those.
I know I can achieve that, using files :

print file('myscript.py','rb').read()

But is there a way / a variable that contains the current file in
memory ?

I don't believe so.

--
Grant Edwards grante Yow! RHAPSODY in Glue!
at
visi.com

[Szabolcs Nagy]

> But is there a way / a variable that contains the current file in

memory ?

yes: import __main__

you can do:

import inspect
import __main__
print inspect.getsource(__main__)

or simply:

print open(__file__).read()
nsz

[Dave Hansen]

On 9 Jan 2006 10:09:19 -0800 in comp.lang.python, "Patrick Allaire"
<pa******@gmail.com> wrote:

How to create a script that list itself ?
Stealing from the old C chestnut:

s="s=%c%s%c;print s%%(34,s,34)";print s%(34,s,34)


I would like to know, where is the script's code is stored once we
start it. I know I can achieve that, using files :

Well, in the above, the script (or rather, the information necessary
to print the script) is actually stored in a string that is part of
the script...

Regards,
-=Dave

--
Change is inevitable, progress is not.

[calfdog]

########################################

import sys

path = os.path.dirname(sys.argv[0])
print "Path:%s" % (path)

######################################

If you ran this as a script,
This would print the location of where the script itself is running.

Hope it helps!

Rob

[Duncan Booth]

Dave Hansen wrote:

Stealing from the old C chestnut:

s="s=%c%s%c;print s%%(34,s,34)";print s%(34,s,34)

Or a bit shorter:

s='s=%s;print s%%`s`';print s%`s`

[Tim Roberts]

Duncan Booth <du**********@invalid.invalid> wrote:

Dave Hansen wrote:

Stealing from the old C chestnut:

s="s=%c%s%c;print s%%(34,s,34)";print s%(34,s,34)

Or a bit shorter:

s='s=%s;print s%%`s`';print s%`s`

It was pointed out to me that the shortest Python program which produces
itself on stdout is:
--
- Tim Roberts, ti**@probo.com
Providenza & Boekelheide, Inc.

[Mike Meyer]

Tim Roberts <ti**@probo.com> writes:

It was pointed out to me that the shortest Python program which produces
itself on stdout is:
--

Which, oddly enough, is also the shortest shell program that produces
itself on stdout.

<mike
--
Mike Meyer <mw*@mired.org> http://www.mired.org/home/mwm/
Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information.