Hi!
I have:
x = {'a':3, 'b':2, 'c':4}
How can I sort x by value? (I tried using sorted() with x.items() - but I
didn't get a dictionary as response.)
My second question:
How can I reduce the dictionary to 2 items (so delete everything after the
first two items)
Thanks in advance.
Best regards,
Markus 4 1807
Markus Franz wrote: Hi!
I have:
x = {'a':3, 'b':2, 'c':4}
How can I sort x by value? (I tried using sorted() with x.items() - but I didn't get a dictionary as response.)
My second question: How can I reduce the dictionary to 2 items (so delete everything after the first two items)
Thanks in advance.
Best regards, Markus
See my reply in de.comp.lang.python
Claudio
This function return a tuple of value-key pairs, sorted by value: x = {'a':3, 'b':2, 'c':4} def sortByValue(myDict):
return sorted( [(v,k) for k,v in myDict.items()] )
If you want to get the first two value-key pairs:
sortByValue(x)[:2]
[(2, 'b'), (3, 'a')]
Hope this helps...
Luis
This function returns a tuple of value-key pairs, sorted by value: x = {'a':3, 'b':2, 'c':4} def sortByValue(myDict):
return sorted( [(v,k) for k,v in myDict.items()] )
If you want to get the first two value-key pairs: sortByValue(x)[:2]
[(2, 'b'), (3, 'a')]
Hope this helps...
Luis
You can't get a dictionary ordered by values, but you can get a list of
key-value pairs ordered by value:
def sortByValue(myDict):
x = sorted( [(v,k) for k,v in myDict.items()] )
return [(k,v) for v,k in x]
For getting only the first two pairs:
sortByValue(x)[:2]
Hope this helps...
Luis This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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