thread end and make main program end also?

> is it the default behavior of thread return? Thank a lot

No.

First of all: your code is clearly _not_ exposing the described behaviour -
you talk about exception handling, but there is none done. And you don't
say anything about what your doing in your "cont'" parts.

If code run in a thread throws an exception that is not handled, the thread
will die.

The program will terminate when the main thread terminates and all other
threads that have setDaemon(False) are terminated. If all the threads
(except main) have setDaemon(True) (as yours has), the program will end
immediately after the main thread terminated.
Read the threading modules docs.

--
Regards,

Diez B. Roggisch

Sorry that i had't show my code clearly.
The exception try and catch at the module function (i.e.
myClass.myfunction(), which like:

#### start code within myClass.py ####
def myfunction(self, dbconnection):
sql_query= 'update table set col=value'
try:
dbconnection.query(sql_query)
result = dbconnection.store_result()
tuple_list = result.fetch_row(0,0)
except MySQLError (errno, strerror):
print "MySQLError, errno: %s, strerror: %s" % (errno, strerror)
return 11
except (errno, strerror): # catch all
print "General Error, errno: %s, strerror: %s" % (errno, strerror)"
return 21
#### end code within myClass.py ####

and let main thread function (thread_function()) to handle the sub
thread function by its return value (mainly are update database,
printing message and continuous to run).

Should the exception catch at main thread function rather than
class function?
Thank for helping.

return 1