Directory structure inside a ZipFile object

[Bulba!]

Hello everyone,

I'm a newbie to Python, learning it and tried to write the script that
would read file, zip it, and put in the target directory. I used
ZipFile module (code below).

It works nice, except the zipfile created contains the directory path
of the source file -- which I do NOT want to recreate. E.g. when
I compress 'c:\\temp\\zz.txt', the resulting zipfile contains not just
'zz.txt' file, but also the whole directory, i.e. first directory
is 'c:', inside of it the directory 'temp' is located, and only then
the 'zz.txt' file is stored.

Changing current directory via os.chdir and then using the
filename itself (zz.txt) doesn't work, i.e. the source directory
structure is still re-created within the zipfile.

Code follows. TIA for reply,
def zf(sfpath, targetdir):
if (sys.platform[:3] == 'win'):
tgfpath=sfpath[2:]
else:
tgfpath=sfpath
zfdir=os.path.dirname(os.path.abspath(targetdir) + tgfpath)
zfname=zfdir + '\\' + os.path.basename(tgfpath) + '.zip'
if(not os.path.isdir(zfdir)):
os.makedirs(zfdir)
archive=ZipFile(zfname, 'w', ZIP_DEFLATED)
print 'zfname ' + zfname
archive.write(sfpath)
archive.close()

zf('c:\\temp\\zz.txt','c:\\tmp\\test1\\test2') zfname c:\tmp\test1\test2\temp\zz.txt.zip

--
"Cultural ecstasy may have billions of participants, but it hardly
has a single friend." -- Charles Freund

[Scott David Daniels]

Bulba! wrote:

tried to read file, zip it, and put in the target directory....

It works nice, except the zipfile created contains the directory path
of the source file -- which I do NOT want to recreate.

Look into the two-argument form of the write command:

import zipfile
archive = zipfile.ZipFile('box.zip', 'w', zipfile.ZIP_DEFLATED)
archive.write('source/somewhere/one.txt', 'name.txt')
archive.write('two.txt', 'another.txt')
archive.close()

--Scott David Daniels
Sc***********@Acm.Org

[Bulba!]

On Thu, 09 Dec 2004 07:42:57 -0800, Scott David Daniels
<Sc***********@Acm.Org> wrote:

Look into the two-argument form of the write command:
Well, I should have guessed that, it works. Thanks!

import zipfile
archive = zipfile.ZipFile('box.zip', 'w', zipfile.ZIP_DEFLATED)
archive.write('source/somewhere/one.txt', 'name.txt')
archive.write('two.txt', 'another.txt')
archive.close()

--Scott David Daniels
Sc***********@Acm.Org

--
It's a man's life in a Python Programming Association.