Hello,
I need to convert the string "FFFFFFFF" to a long. To convert this
string I tried the following: 0xffffffff
-1 0xffffffffL
4294967295L
OK, this is what I want, so I tried
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
s = long("0xffffffff")
ValueError: invalid literal for long(): 0xffffffffL
What can I do?
Thank you in advance.
Stefan 16  3709 
On Fri, 2005-11-18 at 11:04, on******@gmail.com wrote: Hello,
I need to convert the string "FFFFFFFF" to a long. To convert this
string I tried the following: 0xffffffff -1 0xffffffffL 4294967295L
OK, this is what I want, so I tried
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
s = long("0xffffffff")
ValueError: invalid literal for long(): 0xffffffffL
What can I do?
Thank you in advance.
Stefan
Leave out the "0x" prefix and tell long() that you're using base 16:
long("ffffffff", 16)
4294967295L
HTH,
Carsten.
On Fri, 2005-11-18 at 11:04, on******@gmail.com wrote: Hello,
I need to convert the string "FFFFFFFF" to a long. To convert this
string I tried the following: 0xffffffff -1 0xffffffffL 4294967295L
OK, this is what I want, so I tried
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
s = long("0xffffffff")
ValueError: invalid literal for long(): 0xffffffffL
What can I do?
Thank you in advance.
Stefan
Leave out the "0x" prefix and tell long() that you're using base 16:
long("ffffffff", 16)
4294967295L
HTH,
Carsten.
Carsten Haese wrote: OK, this is what I want, so I tried
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
s = long("0xffffffff")
ValueError: invalid literal for long(): 0xffffffffL
What can I do?
Thank you in advance.
Stefan
Leave out the "0x" prefix and tell long() that you're using
base 16:
long("ffffffff", 16) 4294967295L
It's sufficient to tell long() that you're using base 16:
#v+
long('0xffffL', 16)
65535L
#v-
Cheers,
--
Klaus Alexander Seistrup
Copenhagen, Denmark http://seistrup.dk/
Carsten Haese wrote: OK, this is what I want, so I tried
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
s = long("0xffffffff")
ValueError: invalid literal for long(): 0xffffffffL
What can I do?
Thank you in advance.
Stefan
Leave out the "0x" prefix and tell long() that you're using
base 16:
long("ffffffff", 16) 4294967295L
It's sufficient to tell long() that you're using base 16:
#v+
long('0xffffL', 16)
65535L
#v-
Cheers,
--
Klaus Alexander Seistrup
Copenhagen, Denmark http://seistrup.dk/ on******@gmail.com wrote: 0xffffffffL
4294967295L
OK, this is what I want, so I tried
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
int("0xffffffff", 0)
4294967295L
STeVe on******@gmail.com wrote: 0xffffffffL
4294967295L
OK, this is what I want, so I tried
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
int("0xffffffff", 0)
4294967295L
STeVe
Steven Bethard <st************@gmail.com> wrote: on******@gmail.com wrote: s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL int("0xffffffff", 0)
4294967295L
So why does the base argument to int() (or long()) default to
10 and not 0?
--
\S -- si***@chiark.greenend.org.uk -- http://www.chaos.org.uk/~sion/
___ | "Frankly I have no feelings towards penguins one way or the other"
\X/ | -- Arthur C. Clarke
her nu becomež se bera eadward ofdun hlęddre heafdes bęce bump bump bump
Steven Bethard <st************@gmail.com> wrote: on******@gmail.com wrote: s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL int("0xffffffff", 0)
4294967295L
So why does the base argument to int() (or long()) default to
10 and not 0?
--
\S -- si***@chiark.greenend.org.uk -- http://www.chaos.org.uk/~sion/
___ | "Frankly I have no feelings towards penguins one way or the other"
\X/ | -- Arthur C. Clarke
her nu becomež se bera eadward ofdun hlęddre heafdes bęce bump bump bump
Sion Arrowsmith wrote: Steven Bethard <st************@gmail.com> wrote:
on******@gmail.com wrote:
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
>int("0xffffffff", 0)
4294967295L
So why does the base argument to int() (or long()) default to
10 and not 0?
Because it's designed for numbers normal people provide, not for numbers
programmers provide. Normal people see 0123 as being equal to 123, not 83.
Sion Arrowsmith wrote: Steven Bethard <st************@gmail.com> wrote:
on******@gmail.com wrote:
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
>int("0xffffffff", 0)
4294967295L
So why does the base argument to int() (or long()) default to
10 and not 0?
Because it's designed for numbers normal people provide, not for numbers
programmers provide. Normal people see 0123 as being equal to 123, not 83.
On Fri, 18 Nov 2005 11:10:06 -0500, Carsten Haese wrote: s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
s = long("0xffffffff")
ValueError: invalid literal for long(): 0xffffffffL
What can I do?
Thank you in advance.
Stefan
Leave out the "0x" prefix and tell long() that you're using base 16:
long("ffffffff", 16)
4294967295L
Or leave the prefix in, and tell Python to use the prefix to predict the
base:
py> long("0xffffffffL", 0)
4294967295L
--
Steven.
On Fri, 18 Nov 2005 11:10:06 -0500, Carsten Haese wrote: s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
s = long("0xffffffff")
ValueError: invalid literal for long(): 0xffffffffL
What can I do?
Thank you in advance.
Stefan
Leave out the "0x" prefix and tell long() that you're using base 16:
long("ffffffff", 16)
4294967295L
Or leave the prefix in, and tell Python to use the prefix to predict the
base:
py> long("0xffffffffL", 0)
4294967295L
--
Steven.
On Fri, 18 Nov 2005 17:49:50 +0000, Leif K-Brooks wrote: Sion Arrowsmith wrote: Steven Bethard <st************@gmail.com> wrote:
on******@gmail.com wrote:
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
>>int("0xffffffff", 0)
4294967295L
So why does the base argument to int() (or long()) default to
10 and not 0?
Because it's designed for numbers normal people provide, not for numbers
programmers provide. Normal people see 0123 as being equal to 123, not 83.
The base arguments to int() and long() default to base 10 because base 10
is used by just about all people and cultures in the world. Leading zeroes
are mathematically meaningless: 0123 means 0*base**3 + 1*base**2 +
2*base**1 + 3*base**0, which is identical to 123 no matter what base you
choose.
Interpreting 0123 in octal is a sop to programmers who want/need
compatibility to the C bug that changes the meaning of numeric literals
according to the presence or absence of a leading zero. Alas I suspect
that this particular piece of illogic is too ingrained now to ever
eradicate.
--
Steven.
On Fri, 18 Nov 2005 17:49:50 +0000, Leif K-Brooks wrote: Sion Arrowsmith wrote: Steven Bethard <st************@gmail.com> wrote:
on******@gmail.com wrote:
s = long("0xffffffffL")
ValueError: invalid literal for long(): 0xffffffffL
>>int("0xffffffff", 0)
4294967295L
So why does the base argument to int() (or long()) default to
10 and not 0?
Because it's designed for numbers normal people provide, not for numbers
programmers provide. Normal people see 0123 as being equal to 123, not 83.
The base arguments to int() and long() default to base 10 because base 10
is used by just about all people and cultures in the world. Leading zeroes
are mathematically meaningless: 0123 means 0*base**3 + 1*base**2 +
2*base**1 + 3*base**0, which is identical to 123 no matter what base you
choose.
Interpreting 0123 in octal is a sop to programmers who want/need
compatibility to the C bug that changes the meaning of numeric literals
according to the presence or absence of a leading zero. Alas I suspect
that this particular piece of illogic is too ingrained now to ever
eradicate.
--
Steven.
Thank you, for all the good answers. Somehow I overlooked the 'radix'
option in the docs.
S
Thank you, for all the good answers. Somehow I overlooked the 'radix'
option in the docs.
S
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