Regexp question

[Philippe C. Martin]

I realize this is more a regexp question than a python question, but maybe one
of the re object could help me:

I have wish to know how to _no_ match:

This is but an example of the data I handle:

xx xx xx xx xx xx xx [yy yy yy yy yy yy yy] (zz zz zz zz)

I currently can retrieve the three group of logical data blocks with:

l_str = 'xx xx xx xx xx xx xx [yy yy yy yy yy yy yy] (zz zz zz zz)'
p = re.compile(r'([a-f-0-9\s]*) (\[[a-f-0-9\s]*\])
(\([a-f-0-9\s]*\))',re.IGNORECASE) #OK
g = p.search(l_str)
What I would rather do is.

"get the data block that is _not_ between brackets or parenthesis i.e; 'xx xx
xx xx xx xx xx' knowing that the intial string could be:

[yy yy yy yy yy yy yy] xx xx xx xx xx xx xx (zz zz zz zz)
Any clue ?

Regards,

Philippe


--
*********************
Philippe C. Martin
SnakeCard LLC
www.snakecard.com
*********************

[Mitja]

On Wed, 1 Dec 2004 07:48:24 -0600, Philippe C. Martin
<ph*************@sbcglobal.net> wrote:

I realize this is more a regexp question than a python question, but
maybe one
of the re object could help me:

I have wish to know how to _no_ match:

This is but an example of the data I handle:

xx xx xx xx xx xx xx [yy yy yy yy yy yy yy] (zz zz zz zz)

I currently can retrieve the three group of logical data blocks with:

l_str = 'xx xx xx xx xx xx xx [yy yy yy yy yy yy yy] (zz zz zz zz)'
p = re.compile(r'([a-f-0-9\s]*) (\[[a-f-0-9\s]*\])
(\([a-f-0-9\s]*\))',re.IGNORECASE) #OK
g = p.search(l_str)
What I would rather do is.

"get the data block that is _not_ between brackets or parenthesis i.e;
'xx xx
xx xx xx xx xx' knowing that the intial string could be:

[yy yy yy yy yy yy yy] xx xx xx xx xx xx xx (zz zz zz zz)
Any clue ?

regexps seem an overkill for the task at hand.

If data is really as simple as you suggest, you can try the following:

s = 'xx [y y] (z z)'
s = s[:s.index('(')] + s[s.index(')')+1:]
s 'xx [y y] ' s = s[:s.index('[')] + s[s.index(']')+1:]
s 'xx ' s.strip()

'xx'
Relevant lines:
s = s[:s.index('(')] + s[s.index(')'):]
s = s[:s.index('[')] + s[s.index(']')+1:]
s = s.strip()
--
Mitja