I know how to alter the list via list indicies but I would like to know if
there is posibility to write in Python something like:
my @arr = 1..3;
for my $element (@arr) {
$element *= 2;
}
print "@arr\n";
and get the result
-------
2 4 6
--
Matija 8 1530
Aloha,
Matija Papec wrote: my @arr = 1..3; for my $element (@arr) { $element *= 2; } print "@arr\n"; 2 4 6 arr = [1,2,3] print [element*2 for element in arr]
[2, 4, 6]
Wishing a happy day
LOBI
On Mon, 22 Nov 2004 17:21:26 +0100, Matija Papec <mp****@yahoo.com> wrote: I know how to alter the list via list indicies but I would like to know if there is posibility to write in Python something like:
my @arr = 1..3; for my $element (@arr) { $element *= 2; } print "@arr\n";
For instance :
arr = 1, 2, 3 # range(1, 4)
arr = [ element*2 for element in arr ]
print arr # [2, 4, 6] it is a list
for element in arr:
print element, # note the comma
print # useful if not in interactive mode only
Read the documentation about "list comprehension" and get the result ------- 2 4 6
Matija Papec wrote: I know how to alter the list via list indicies but I would like to know if there is posibility to write in Python something like:
my @arr = 1..3; for my $element (@arr) { $element *= 2; } print "@arr\n";
and get the result ------- 2 4 6
Something like this?
arr= range(1,4)
for index, value in enumerate( arr):
arr[index]*= 2
print arr
Regards,
Will McGugan
Will McGugan wrote: Matija Papec wrote: I know how to alter the list via list indicies but I would like to know if there is posibility to write in Python something like:
my @arr = 1..3; for my $element (@arr) { $element *= 2; } print "@arr\n";
and get the result ------- 2 4 6
Something like this?
arr= range(1,4) for index, value in enumerate( arr): arr[index]*= 2
But for this you won't need enumerate:
One of
for index in range(len(arr)):
for index in xrange(len(arr)):
is sufficient.
Reinhold
--
[Windows ist wie] die Bahn: Man muss sich um nichts kuemmern, zahlt fuer
jede Kleinigkeit einen Aufpreis, der Service ist mies, Fremde koennen
jederzeit einsteigen, es ist unflexibel und zu allen anderen Verkehrs-
mitteln inkompatibel. -- Florian Diesch in dcoulm
Reinhold Birkenfeld wrote: But for this you won't need enumerate: for index in range(len(arr)):
Isn't the range(len(arr)) construct somewhat of an
contraption? It has become a recognizable pattern
of course but that was by necessity rather than
correctness.
Istvan.
X-Ftn-To: Jp Calderone
Jp Calderone <ex*****@divmod.com> wrote: ------- 2 4 6
No. Integers in Python are immutable. For lists of other things, mutation in-place (similar to the above example) is possible, but for integers and other immutable types, it is not. You may be interested in list comprehensions, though:
arr = range(1, 4) arr[:] = [a * 2 for a in arr] print arr
I guess this works like "map" but "for" is more idimatic.
Thank you all for so quick responses. :)
--
Matija
Matija Papec wrote: X-Ftn-To: Jp Calderone
Jp Calderone <ex*****@divmod.com> wrote: ------- 2 4 6
No. Integers in Python are immutable. For lists of other things, mutation in-place (similar to the above example) is possible, but for integers and other immutable types, it is not. You may be interested in list comprehensions, though:
arr = range(1, 4) arr[:] = [a * 2 for a in arr] print arr
I guess this works like "map" but "for" is more idimatic.
Yes. List comprehensions are elegant (and fast) expressions you would
otherwise construct with map() and filter().
Reinhold
--
[Windows ist wie] die Bahn: Man muss sich um nichts kuemmern, zahlt fuer
jede Kleinigkeit einen Aufpreis, der Service ist mies, Fremde koennen
jederzeit einsteigen, es ist unflexibel und zu allen anderen Verkehrs-
mitteln inkompatibel. -- Florian Diesch in dcoulm
>> arr[:] = [a * 2 for a in arr] print arr
I guess this works like "map" but "for" is more idimatic.
idiomatic
--
Matija This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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