Hi all,
I want to define 'in' operator (or any "magic" function) on list which
returns True value if all of list (i.e. _list) elements appears in other
list (i.e. L) in the same order and False otherwise. By way of example:
L = [1, 2, 3, 4, 5, 6, 7]
_list = [3, 4, 5]
if L2 in L0:
return True
else:
return False
How to do that?
--
..:: sjf ::..
"Linux is like Wigwam. No gates, no windows... Apache inside ;-)" 11 1816
...:: sjf ::.. wrote: I want to define 'in' operator (or any "magic" function) on list which returns True value if all of list (i.e. _list) elements appears in other list (i.e. L) in the same order and False otherwise.
How about : def containedinsequence(short, long):
ilong = iter(long)
for s in short:
for l in ilong:
if s==l:
break
else:
return False # ran out of long list
return True
L = [1, 2, 3, 4, 5, 6] containedinsequence([3, 4, 6], L)
True containedinsequence([3, 4, 7], L)
False containedinsequence([3, 4, 3], L)
False containedinsequence([], L)
True
pewnego dnia niejaki(a) Duncan Booth wstukal(a) byl(a) co nastepuje...: ..:: sjf ::.. wrote:
I want to define 'in' operator (or any "magic" function) on list which returns True value if all of list (i.e. _list) elements appears in other list (i.e. L) in the same order and False otherwise.
How about:
def containedinsequence(short, long): ilong = iter(long) for s in short: for l in ilong: if s==l: break else: return False # ran out of long list return True
L = [1, 2, 3, 4, 5, 6] containedinsequence([3, 4, 6], L)
OK, this is nearly what I am expecting, but I want if
containedsequence([3, 4, 5], L) returns True, but
containedsequence([3, 4, 6], L) returns False
because that sequence not exist in longlist exactly
--
..:: sjf ::..
"Linux is like Wigwam. No gates, no windows... Apache inside ;-)"
On Mon, Oct 11, 2004 at 11:53:36AM +0200, ..:: sjf ::.. wrote: Hi all,
I want to define 'in' operator (or any "magic" function) on list which returns True value if all of list (i.e. _list) elements appears in other list (i.e. L) in the same order and False otherwise. By way of example:
L = [1, 2, 3, 4, 5, 6, 7] _list = [3, 4, 5]
if L2 in L0: return True else: return False
How to do that?
You might find that the 'sets' module does what you need.
On Mon, 11 Oct 2004 12:51:57 +0200, "..:: sjf ::.." <so******@unknown.org> wrote: pewnego dnia niejaki(a) Duncan Booth wstukal(a) byl(a) co nastepuje...: ..:: sjf ::.. wrote:
I want to define 'in' operator (or any "magic" function) on list which returns True value if all of list (i.e. _list) elements appears in other list (i.e. L) in the same order and False otherwise.
How about:
>def containedinsequence(short, long):
ilong = iter(long) for s in short: for l in ilong: if s==l: break else: return False # ran out of long list return True
>L = [1, 2, 3, 4, 5, 6] >containedinsequence([3, 4, 6], L)
OK, this is nearly what I am expecting, but I want if containedsequence([3, 4, 5], L) returns True, but containedsequence([3, 4, 6], L) returns False because that sequence not exist in longlist exactly
Not very tested (just what you see ;-) def issubseq(sub,seq):
... if not sub: return True
... sub0 = sub[0]
... start = 0
... lensub = len(sub)
... while True:
... try: start = seq.index(sub0, start)
... except ValueError: return False
... if seq[start:start+lensub] == sub: return True
... start +=1
... return False
... L = [1, 2, 3, 4, 5, 6] issubseq([3,4,5],L)
True issubseq([3,4,6],L)
False issubseq([3],L)
True issubseq([],L)
True issubseq([6],L)
True issubseq([1,2],L)
True
Regards,
Bengt Richter
Phil Frost wrote: On Mon, Oct 11, 2004 at 11:53:36AM +0200, ..:: sjf ::.. wrote:
Hi all,
I want to define 'in' operator (or any "magic" function) on list which returns True value if all of list (i.e. _list) elements appears in other list (i.e. L) in the same order and False otherwise. By way of example:
L = [1, 2, 3, 4, 5, 6, 7] _list = [3, 4, 5]
if L2 in L0: return True else: return False
How to do that?
You might find that the 'sets' module does what you need.
The OP said he cares about order, so sets will certainly *not* do what
he wants. I suggest looking up string matching algorithms. This is
effectively what has been asked for but for strings of numbers instead
of strings of characters.
Aaron
pewnego dnia niejaki(a) Bengt Richter wstukal(a) byl(a) co nastepuje...: On Mon, 11 Oct 2004 12:51:57 +0200, "..:: sjf ::.." <so******@unknown.org> wrote:
pewnego dnia niejaki(a) Duncan Booth wstukal(a) byl(a) co nastepuje...:
..:: sjf ::.. wrote: I want to define 'in' operator (or any "magic" function) on list which returns True value if all of list (i.e. _list) elements appears in other list (i.e. L) in the same order and False otherwise.
How about: >>def containedinsequence(short, long):
ilong = iter(long) for s in short: for l in ilong: if s==l: break else: return False # ran out of long list return True >>L = [1, 2, 3, 4, 5, 6] >>containedinsequence([3, 4, 6], L) OK, this is nearly what I am expecting, but I want if containedsequence([3, 4, 5], L) returns True, but containedsequence([3, 4, 6], L) returns False because that sequence not exist in longlist exactly
Not very tested (just what you see ;-)
It seems it works! Thanks very much!
--
..:: sjf ::..
"Linux is like Wigwam. No gates, no windows... Apache inside ;-)"
Duncan Booth wrote: def containedinsequence(short, long):
It's probably a good idea not to shadow the long built-in.
--
Michael Hoffman
Phil Frost wrote: [sjf]I want to define 'in' operator (or any "magic" function) on list which returns True value if all of list (i.e. _list) elements appears in other list (i.e. L) in the same order and False otherwise. By way of example: You might find that the 'sets' module does what you need.
Those sets are not ordered.
--
Michael Hoffman
Michael Hoffman wrote: Duncan Booth wrote:>def containedinsequence(short, long):
It's probably a good idea not to shadow the long built-in.
Relax. It's only shadowed inside a function that doesn't use the builtin
anyway.
Peter
PS: For me to make that U-turn it took GvR pointing out the obvious: http://mail.python.org/pipermail/pyt...ly/045948.html
Peter Otten wrote: Michael Hoffman wrote:It's probably a good idea not to shadow the long built-in.
Relax. It's only shadowed inside a function that doesn't use the builtin anyway.
I can see that, but I was thinking mainly in terms of avoiding warnings and problems if the Python developers eventually try to optimize references to the builtins :)
--
Michael Hoffman
Michael Hoffman wrote: Peter Otten wrote: Michael Hoffman wrote:It's probably a good idea not to shadow the long built-in.
Relax. It's only shadowed inside a function that doesn't use the builtin anyway.
I can see that, but I was thinking mainly in terms of avoiding warnings and problems if the Python developers eventually try to optimize references to the builtins :)
I can see how assigning to a global can cause trouble here, but a local
should be easy to resolve at compile time as 'not the builtin' and
therefore not hinder optimization.
Peter This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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