Steven Arnold wrote:
Is there a more elegant way to construct \[a-z] in a string than
something like:
s = '\\n'
result = eval( "'%s'" ) % s
Another ugly method would be to build a dict with all the different
special letters I want as keys, and their corresponding values as
values. Or I could have a huge if/elif structure. I can't make ord
work, because while ord( '\n' ) gives me a reasonable integer that I
can interpolate with %c, I don't have '\n', I have '\\n'.
No, you actually *do* have '\n', the single byte that represents ASCII
linefeed.
len('\n')
1 len('\\n')
2 ord('\n')
10 ord('\\n')
Traceback (most recent call last):
File "<interactive input>", line 1, in ?
TypeError: ord() expected a character, but string of length 2 found for char in '\\n':
.... print ord(char)
....
92
110
Note that '\n' is a single byte, while '\\n' is two bytes. In the first
case, '\n' is interpreted as the single LF byte. In the second case,
'\\' collapses into a single backslash, giving you a backslash byte and
a 'n' byte.
When you type a string literal containing a backslash, if that backslash
can combine with the following character to make a valid escape code, it
*will* do so unless you've explicitly turned off escaping (by, e.g.,
using raw strings). Of course, if the combination is *not* a valid
escape code, then the backslash and following character will be
interpreted normally.
Jeff Shannon
Technician/Programmer
Credit International
