getting the function name

[beliavsky]

Is there a way in Python to print the name of the function one is
currently in?
The code

def foo():
debug = True
if (debug):
print "entered",__name__

x = foo()

outputs "entered __main__"

I want to print "entered foo". Of course I could just hard-code the
string "foo" in a print statement, but I don't want to have the
function name written in more than one place.

[Mathias Waack]

be*******@aol.com wrote:

Is there a way in Python to print the name of the function one is
currently in?

def f(): .... tb = traceback.extract_stack()
.... print tb[-1][2] f()

f

I'm using a more comfortable way by setting a global debug flag and
enabling tracing (see sys.settrace). This gives you the same feature
without adding code to each function.

Mathias

[Russell Blau]

<be*******@aol.com> wrote in message
news:30**************************@posting.google.c om...

Is there a way in Python to print the name of the function one is
currently in?

Google is your friend:

http://groups.google.com/groups?thre...eton.ca&rnum=1

Also
http://groups.google.com/groups?thre...ews.com&rnum=1

--
I don't actually read my hotmail account, but you can replace hotmail with
excite if you really want to reach me.

[Sean Ross]

"Russell Blau" <ru******@hotmail.com> wrote in message
news:2r*************@uni-berlin.de...

<be*******@aol.com> wrote in message
news:30**************************@posting.google.c om...

Is there a way in Python to print the name of the function one is
currently in?
Google is your friend:

http://groups.google.com/groups?thre...eton.ca&rnum=1

Hi.

The posting that the above link refers to was made by me, but I'd like to
suggest that you do not use the code presented there (def WhoMightIBe()).
That was just a bit of a failed experiment to see whether I could track down
the name of a function _after_it_had_been_aliased_. What the OP wants is the
recipe (by Alex Martelli [1]) quoted in the posting I made previous to this
one. I regret posting that experiment now - It was fun to try, but I think
it casts more shadow than light.

Good luck,
Sean

[1] http://aspn.activestate.com/ASPN/Coo...n/Recipe/66062