Is there an easier way to do this:
def print_whats_returned(function):
print function
print type(function) 10 1675
Brad Tilley wrote: Is there an easier way to do this:
def print_whats_returned(function): print function print type(function)
What is "this"? The subject line and the name of
the function imply it is something to do with the
return values of a function, yet the function is
never called. While Python is sometimes called
executable pseudo-code, I think in this case you'd
be better off using plain English to describe what
your goal is.
-Peter
Peter Hansen wrote: Brad Tilley wrote:
Is there an easier way to do this:
def print_whats_returned(function): print function print type(function)
What is "this"? The subject line and the name of the function imply it is something to do with the return values of a function, yet the function is never called. While Python is sometimes called executable pseudo-code, I think in this case you'd be better off using plain English to describe what your goal is.
-Peter
OK,
def print_whats_returned(function):
## A function that shows what another function has returned
## as well as the 'type' of the returned data.
print function
print type(function)
def send_net_params_to_admin(ip_param, port_param):
ip = get_server_ip()
port = get_server_port()
return ip, port
print_whats_returned(send_net_params_to_admin(get_ server_ip(),
get_server_port()))
On Wed, 15 Sep 2004 13:30:22 -0400, Brad Tilley <br********@usa.net> wrote: Peter Hansen wrote: Brad Tilley wrote:
Is there an easier way to do this:
def print_whats_returned(function): print function print type(function)
What is "this"? The subject line and the name of the function imply it is something to do with the return values of a function, yet the function is never called. While Python is sometimes called executable pseudo-code, I think in this case you'd be better off using plain English to describe what your goal is.
-Peter
OK,
def print_whats_returned(function): ## A function that shows what another function has returned ## as well as the 'type' of the returned data. print function print type(function)
def send_net_params_to_admin(ip_param, port_param): ip = get_server_ip() port = get_server_port() return ip, port
print_whats_returned(send_net_params_to_admin(get_ server_ip(), get_server_port()))
def send_net_params_to_admin(ip_param, port_param):
ip = get_server_ip()
port = get_server_port()
return ip, port
print send_net_params_to_damin(ip_param, port_param)
In article <ci**********@solaris.cc.vt.edu>,
Brad Tilley <br********@usa.net> wrote: Is there an easier way to do this:
def print_whats_returned(function): print function print type(function)
In the general case, this is not possible. A function can return
different things at different times. Consider the following function:
def getSomething ():
if random.random () < 0.5:
return 42
else:
return "fourty-two"
so what type would you say this returns?
Roy Smith wrote: In article <ci**********@solaris.cc.vt.edu>, Brad Tilley <br********@usa.net> wrote:
Is there an easier way to do this:
def print_whats_returned(function): print function print type(function)
In the general case, this is not possible. A function can return different things at different times. Consider the following function:
def getSomething (): if random.random () < 0.5: return 42 else: return "fourty-two"
so what type would you say this returns?
Depends on what randon.random came up with. Either way, we'd know what
the function returned and what type it was... and that's all I want to know.
> > def print_whats_returned(function): ## A function that shows what another function has returned ## as well as the 'type' of the returned data. print function print type(function)
This function does not do what you are expecting; type(function) does
not return the type that function returns, it returns the type of the
object passed in.
def foo():
return 42 print foo
<function foo at 0xf6f888ec> print type(foo)
<type 'function'>
Because Python is a dynamically typed language, it is not possible for
the interpreter to know what type of object a function returns without
executing it. In fact, it is possible for a function to return
different kinds of things. For example:
def bar(x):
if x == 0:
return 42
elif x== 1:
return "Forty-two"
else:
return None
In a statically typed language, like C, we neccessarily know what type
of thing is returned and we know it at compile-time. In Python, the
type of the returned object is only bound at run-time. In practice,
this means that we usually have to "just know" what a function returns
by knowing the intended semantics of the function. That said, you
could write a function like this that tells you about the return type
of a function for a given invocation of that function ...
def characterize(f, *args):
r = f(*args)
print type(r)
characterize(bar, 0)
<type 'int'> characterize(bar, 1)
<type 'str'> characterize(bar, 2)
<type 'NoneType'>
Hope this helps.
Pete
Peter Grayson wrote: This function does not do what you are expecting; type(function) does not return the type that function returns, it returns the type of the object passed in.
def foo(): return 42
print foo <function foo at 0xf6f888ec> print type(foo) <type 'function'>
Because Python is a dynamically typed language, it is not possible for the interpreter to know what type of object a function returns without executing it. In fact, it is possible for a function to return different kinds of things. For example:
def bar(x): if x == 0: return 42 elif x== 1: return "Forty-two" else: return None
In a statically typed language, like C, we neccessarily know what type of thing is returned and we know it at compile-time. In Python, the type of the returned object is only bound at run-time. In practice, this means that we usually have to "just know" what a function returns by knowing the intended semantics of the function. That said, you could write a function like this that tells you about the return type of a function for a given invocation of that function ...
def characterize(f, *args): r = f(*args) print type(r)
characterize(bar, 0) <type 'int'> characterize(bar, 1) <type 'str'> characterize(bar, 2)
<type 'NoneType'>
Hope this helps.
Pete
Yes, it was very helpful. Thanks Pete.
Brad Tilley wrote: def print_whats_returned(function): ## A function that shows what another function has returned ## as well as the 'type' of the returned data. print function print type(function)
def send_net_params_to_admin(ip_param, port_param): ip = get_server_ip() port = get_server_port() return ip, port
print_whats_returned(send_net_params_to_admin(get_ server_ip(), get_server_port()))
Note here that the argument to print_whats_returned() is *not* a
function; it is the value returned from a function. You're not passing
the function send_net_params_to_admin(); you're passing whatever is
returned from it. It is effectively equivalent to the following:
return_value = send_net_params_to_admin(get_server_ip(),
get_server_port())
print_whats_returned(return_value)
Thus, your function would be much more clear with different names, since
it really has nothing to do with functions.
def print_value_and_type(value):
print value
print type(value)
With these names, you wouldn't have had all of these people talking
about dynamic typing and such, because it would've been clear that
you're not attempting to find the intended return value of a theoretical
future function call, but rather trying to inspect the actual value
that's already been returned by a previously-executed function call.
And no, there isn't really an easier way to do this. :)
Jeff Shannon
Technician/Programmer
Credit International
Jeff Shannon wrote: Brad Tilley wrote:
def print_whats_returned(function): ## A function that shows what another function has returned ## as well as the 'type' of the returned data. print function print type(function)
def send_net_params_to_admin(ip_param, port_param): ip = get_server_ip() port = get_server_port() return ip, port
print_whats_returned(send_net_params_to_admin(get_ server_ip(), get_server_port()))
Note here that the argument to print_whats_returned() is *not* a function; it is the value returned from a function. You're not passing the function send_net_params_to_admin(); you're passing whatever is returned from it. It is effectively equivalent to the following:
return_value = send_net_params_to_admin(get_server_ip(), get_server_port()) print_whats_returned(return_value)
Thus, your function would be much more clear with different names, since it really has nothing to do with functions.
def print_value_and_type(value): print value print type(value)
With these names, you wouldn't have had all of these people talking about dynamic typing and such, because it would've been clear that you're not attempting to find the intended return value of a theoretical future function call, but rather trying to inspect the actual value that's already been returned by a previously-executed function call. And no, there isn't really an easier way to do this. :)
Jeff Shannon Technician/Programmer Credit International
Thanks Jeff,
You said what I was trying to say better than I could say it. I'm not
crazy after all... just picked the wrong words. This made sense to me at
first, then everyone said, "You can't do that," and I was almost at the
point of believing them when you posted. ;)
Brad
On Wed, 15 Sep 2004 13:30:22 -0400, Brad Tilley <br********@usa.net>
declaimed the following in comp.lang.python: def print_whats_returned(function): ## A function that shows what another function has returned ## as well as the 'type' of the returned data. print function print type(function)
def send_net_params_to_admin(ip_param, port_param):
Why are you passing parameters for IP and port? You never use
them!
ip = get_server_ip() port = get_server_port() return ip, port
print_whats_returned(send_net_params_to_admin(get_ server_ip(), get_server_port()))
And here you are invoking get_server_ip and get_server_port,
passing the values to a function that throws them away, because IT is
calling the same functions.
You can throw away the whole send_net_params_to_admin function
since all it is really returning is the same stuff you passed in (after
the overhead of ignoring what you passed in and recomputing them)
Your entire example condenses down to:
ip_port = (get_server_ip(), get_server_port())
print ip_port
print type(ip_port)
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