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has_method


Hi All!

Does anyone knows how to tell if an object has a method with a given
name? How can I access that method?

For attributes, it is easy:

class A(object):
a = 12
b = 'Python'

a = A()
a.__dict__.has_key('a') # True
a.__dict__.has_key('b') # True
a.__dict__.has_key('c') # False

But it won't work for methods. Thanks in advance.

Laci 2.0
Jul 18 '05 #1
4 3109
Gandalf wrote:

Hi All!

Does anyone knows how to tell if an object has a method with a given
name? How can I access that method?

For attributes, it is easy:

class A(object):
a = 12
b = 'Python'

a = A()
a.__dict__.has_key('a') # True
a.__dict__.has_key('b') # True
a.__dict__.has_key('c') # False

But it won't work for methods. Thanks in advance.

Laci 2.0

Well, one way is try/except:

try:
a.someMethod(arg1, arg2)
except AttributeError:
print "Aarrgghh!"

regards
Steve
Jul 18 '05 #2
Gandalf wrote:

Does anyone knows how to tell if an object has a method with a given
name? How can I access that method?

For attributes, it is easy:

class A(object):
a = 12
b = 'Python'

a = A()
a.__dict__.has_key('a') # True
a.__dict__.has_key('b') # True
a.__dict__.has_key('c') # False

But it won't work for methods. Thanks in advance.


Don't access __dict__ directly. In fact, most of the time
the presence of the __ underscores is to warn you that you
are doing something unusual... here's the better way:

if callable(getattr(a, 'b')):
print 'has a method called b'
else:
print 'no method called b'

getattr(obj, name) retrieves the attribute, and callable()
checks if it's a method (roughly speaking... not quite but
good enough for your purposes I believe). Look in the docs
for the __builtin__ module to learn about these and other
such useful functions.
http://docs.python.org/lib/built-in-...built-in-funcs

-Peter
Jul 18 '05 #3
Well, one way is try/except:

try:
a.someMethod(arg1, arg2)
except AttributeError:
print "Aarrgghh!"

But since I have my method name in a variable, it will be this way:

methods = dir(self)
if methodname in methods:
cmd = "self." + methodname
method = eval(cmd)

This is what I wanted to avoid - i.e. the use of eval. There must be an
easier and quicker way to do this.
Jul 18 '05 #4
Gandalf wrote:
But since I have my method name in a variable, it will be this way:

methods = dir(self)
if methodname in methods:
cmd = "self." + methodname
method = eval(cmd)

This is what I wanted to avoid - i.e. the use of eval. There must be an
easier and quicker way to do this.


method = getattr(self, methodname, None)
if method:
method(arg1, arg2)

Note that this may still fail if the attribute's value is not callable (and
bool(method) True).
Use

try:
method(arg1, arg2)
except TypeError:
pass

to guard against that.

Peter

Jul 18 '05 #5

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