In the following code, t1 does not modify b, while t2 seems to
modify b. What do I need to do in order to make b local in t2
so that b.remove() does not modify the passed in list?
def t1(a,b):
b = []
def t2(a,b):
b.remove(4)
a=[1,2,3]
b=[4,5]
t1(a,b)
print a,b
t2(a,b)
print a,b
results:
[1, 2, 3] [4, 5]
[1, 2, 3] [5]
Many TIA!
Mark
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Mark Harrison
Pixar Animation Studios