Hi.
Today I created a script called load.py for using at the command line
written in Python 2.3.
This script should load as many websites as given on the comand line and
print them with a seperation string to stdout. The loading was done in
parallel. (I used processes for this.)
The script was started by the following command:
../load.py en 58746 http://www.python.com
Well, everything was fine. Then I wanted to load a second website and so I
started the script with the following command:
../load.py en 58746 http://www.python.com http://www.linux.org
The behaviour was strange: The last website (http://www.linux.org) was
loaded and printed twice.
Then I started the script for a third time with the following command:
../load.py en 58746 http://www.python.com http://www.linux.org
http://www.suse.com
The result was: First websites was loaded and shown once, second website
twice, and the third website was loaded and shown for four times!
(This behaviour occurs with ANY address given to the script...)
Does anybody know an answer to my problem???
Thank you.
Best regards
Markus Franz
(some information about my computer: Python 2.3, SuSE Linux 9.0 Pro with
Kernel 2.4)
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My script:
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#!/usr/bin/python
import urllib2, sys, socket, os, string
# set timeout
socket.setdefaulttimeout(4)
# function for loading and printing a website
def myfunction(url):
try:
req = urllib2.Request(url)
req.add_header('Accept-Language', sys.argv[1])
req.add_header('User-Agent', 'Mozilla/4.0 (compatible; MSIE 6.0;
Windows NT 5.1)')
f = urllib2.urlopen(req)
contents = f.read()
output = "\n---PI001---" + sys.argv[2] + '---PI001---' + '---PI002-'
+ sys.argv[2] + '::' + f.geturl() + '::' + sys.argv[2] + "-PI002---\n" +
contents
print output
del output
f.close()
del contents
del f
del req
except:
pass
# start processes
for currenturl in sys.argv:
if currenturl != sys.argv[0] and currenturl != sys.argv[1] and
currenturl != sys.argv[2]:
PID = os.fork()
if PID == 0:
myfunction(currenturl)
exit
