Create static method dynamically

[Salvatore]

Hello,

Here is my problem :

class myClass:
def addmethod(name,method):
maClasse.__dict__[name] = method
addmethod = staticmethod(addmethod)

def hello():
print "hello"

myClasse.addmethod('hello',hello)
Traceback (most recent call last):
File "<pyshell#0>", line 1, in -toplevel-
myClass.hello()
TypeError: unbound method hello() must be called with myClass instance
as first argument (got nothing instead)

I would like to make this call:
myClass.hello()

Is there a way of making 'hello' a
static method of 'myClass ?

Regards

[Peter Otten]

Salvatore wrote:

def hello():
print "hello" Is there a way of making 'hello' a
static method of 'myClass ?

class Test: .... def addStaticMethod(name, func):
.... setattr(Test, name, staticmethod(func))
.... addStaticMethod = staticmethod(addStaticMethod)
.... def hello(): print "hello" .... t = Test()
t.addStaticMethod("hello", hello)
t.hello() hello
Even simpler, if you know the method name beforehand:
Test.world = staticmethod(hello)
t.world()

hello

Peter

[Salvatore]

As I always say, the beauty is in the simplicity :-)
Thank you very much Peter

Regards

Salvatore

[Leif K-Brooks]

Salvatore wrote:

class myClass:
def addmethod(name,method):
maClasse.__dict__[name] = method
addmethod = staticmethod(addmethod)

def hello():
print "hello"

myClasse.addmethod('hello',hello) <snip> I would like to make this call:
myClass.hello()

Change line 3 to:
myClass.__dict__[name] = staticmethod(method)

[Salvatore]

Leif K-Brooks wrote:

Change line 3 to:
myClass.__dict__[name] = staticmethod(method)

That make me feel not very proud ;-)
Thans Leif