Python newbie advice needed!
I'm tring to write what I would have expressed in Perl as
my ($a, $b, $c) = @array;
This is very similar to the python statement
a, b, c = array
BUT, the Python will throw an exception if array isn't exactly 3
elements long, wheras the Perl will work for any length of @array,
either throwing away excess elements or setting the variables to
undef, ie like this
if len(array) >= 1:
a = array[0]
else:
a = None
if len(array) >= 2:
b = array[1]
else:
b = None
if len(array) >= 3:
c = array[2]
else:
c = None
This works if array has >= 3 elements
a, b, c = array[:3]
And this works however many elements array has
a, b, c = (array + 3*[None])[:3]
but it doesn't seem very Pythonic - is there a better way?
--
Nick Craig-Wood nc*@axis.demon.co.uk 4 1203
In the specific case where you're trying to map a variable-length
argument list to local variables in a function, you can do the more
Pythonic:
def myfunc (a = None, b = None, c = None)
I'd say the answer is similar for other tasks. There's probably a
Pythonic way to do the overall task as opposed to a
statement-by-statement translation. I'm tring to write what I would have expressed in Perl as
my ($a, $b, $c) = @array;
This is very similar to the python statement
a, b, c = array
BUT, the Python will throw an exception if array isn't exactly 3 elements long, wheras the Perl will work for any length of @array, either throwing away excess elements or setting the variables to undef, ie like this
if len(array) >= 1: a = array[0] else: a = None if len(array) >= 2: b = array[1] else: b = None if len(array) >= 3: c = array[2] else: c = None
This works if array has >= 3 elements
a, b, c = array[:3]
And this works however many elements array has
a, b, c = (array + 3*[None])[:3]
but it doesn't seem very Pythonic - is there a better way?
-- Nick Craig-Wood nc*@axis.demon.co.uk -- http://mail.python.org/mailman/listinfo/python-list
"Nick Craig-Wood" <nc*@axis.demon.co.uk> wrote in message
news:sl****************@irishsea.home.craig-wood.com... Python newbie advice needed!
I'm tring to write what I would have expressed in Perl as
my ($a, $b, $c) = @array;
This is very similar to the python statement
a, b, c = array
BUT, the Python will throw an exception if array isn't exactly 3 elements
long,
This is an intentional feature. Mismatches are often bugs.
wheras the Perl will work for any length of @array, either throwing away excess elements or setting the variables to undef, ie like this
Guido's philosophy is that the interpreter should resist guessing like this
when code is at least half likely to be buggy.
And this works however many elements array has
a, b, c = (array + 3*[None])[:3]
but it doesn't seem very Pythonic - is there a better way?
Being explicitly generic is Pythonic to me. Or do something like
a=b=c=None
try: c=array[2]
try: b=array[1]
try: a=array[1]
except: pass
except: pass
except: pass
but I prefer the one liner here. It is easier to extend to more names.
Terry J. Reedy
Wayne Folta <wf****@netmail.to> wrote: In the specific case where you're trying to map a variable-length argument list to local variables in a function, you can do the more Pythonic:
def myfunc (a = None, b = None, c = None)
Interesting... I was thinking in particular of sys.argv with this
example, but the above gave me the idea below which would work quite
well (imagine sys.argv in place of L below) def f(a=None,b=None,c=None,*extra): print a,b,c
.... L=[]; apply(f,L)
None None None L=[1]; apply(f,L)
1 None None L=[1,2]; apply(f,L)
1 2 None L=[1,2,3]; apply(f,L)
1 2 3 L=[1,2,3,4]; apply(f,L)
1 2 3 L=[1,2,3,4,5]; apply(f,L)
1 2 3
--
Nick Craig-Wood nc*@axis.demon.co.uk
"Nick Craig-Wood" <nc*@axis.demon.co.uk> wrote in message
news:sl***************@irishsea.home.craig-wood.com... def myfunc (a = None, b = None, c = None)
def f(a=None,b=None,c=None,*extra): print a,b,c
... L=[]; apply(f,L)
You can now write 'apply(f,L)' as f(*L) and be future-proof in case apply
disappears
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