stat doesn't work!

[Paulo Pinto]

I am doing an application that needs to
know when it is manipulating symbolic links.

But it is failing to reckognize them.

If I run the following code:

<code>
import sys
import os
from stat import *

mode = os.stat(sys.argv[1])[ST_MODE]
if S_ISLNK(mode):
print 'File is a link'
else:
print 'Just a normal file'
</code>
I will alway get the 'Just a normal file'
message even though I am using a symbolic
link as argument.

I've done the same example in Perl and in
bash and it works.

Could this be a bug in my Python version
(2.2.2) or I am doing something wrong ?

Thanks in advance,
Paulo Pinto

[Jeff Epler]

On Mon, Feb 09, 2004 at 05:10:31PM +0100, Paulo Pinto wrote:

I am doing an application that needs to
know when it is manipulating symbolic links.

try os.lstat.

import os
from stat import *
S_ISLNK(os.stat("/proc/self").st_mode) 0 S_ISLNK(os.lstat("/proc/self").st_mode)

1

Jeff

[Donn Cave]

In article <c0**********@sunnews.cern.ch>,
Paulo Pinto <pa*********@cern.ch> wrote:

I am doing an application that needs to
know when it is manipulating symbolic links.

That's a special case, and therefore you have
to use a special version of stat(). stat()
will follow the link, so you get the original
file. lstat() will report the link itself.

Donn Cave, do**@u.washington.edu

[Paulo Pinto]

It works now.
Thanks for your answers.

Paulo Pinto wrote:

I am doing an application that needs to
know when it is manipulating symbolic links.

But it is failing to reckognize them.

If I run the following code:

<code>
import sys
import os
from stat import *

mode = os.stat(sys.argv[1])[ST_MODE]
if S_ISLNK(mode):
print 'File is a link'
else:
print 'Just a normal file'
</code>
I will alway get the 'Just a normal file'
message even though I am using a symbolic
link as argument.

I've done the same example in Perl and in
bash and it works.

Could this be a bug in my Python version
(2.2.2) or I am doing something wrong ?

Thanks in advance,
Paulo Pinto