Identifying Caller

[Tonguç Yumruk]

Is there a way to identify the caller of a function? For example:

def foo():
print <Caller Functions name>

def bar():
foo()

I want foo to print "bar"... And it will be great if I can also detect
call is came from which module.

Thanks.

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Tonguç Yumruk

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[Robin Becker]

In article <ma************************************@python.org >, Tonguç
Yumruk <tr*****@ttnet.net.tr> writes

Is there a way to identify the caller of a function? For example:

def foo():
print <Caller Functions name>

def bar():
foo()

I want foo to print "bar"... And it will be great if I can also detect
call is came from which module.

Thanks.

try something like this

#############################
def who_called_me(n=0):
import sys
f = sys._getframe(n)
c = f.f_code
return c.co_filename, c.co_name, f.f_lineno

if __name__=='__main__':
def test2():
print 'test2',who_called_me(1)

def test1():
print 'test1',who_called_me(1)
test2()

def test():
print 'test',who_called_me(1)
test1()
test2()

class dingo:
def __init__(self):
self.a = 1
print '__init__',who_called_me(1)
def doit(self):
print 'dingo.doit',who_called_me(1), self.a
def calldoit(self):
print 'dingo.calldoit',who_called_me(1), self.a
self.doit()
test()
def mongo():
print 'mongo', who_called_me(1)
d=dingo()
d.doit()
d.calldoit()
test()
test1()
test2()
mongo()
--
Robin Becker

[Alex Martelli]

Tonguç Yumruk wrote:

Is there a way to identify the caller of a function? For example:

def foo():
print <Caller Functions name>

def bar():
foo()

I want foo to print "bar"... And it will be great if I can also detect
call is came from which module.

See function _getframe in module sys. The frame object that
it returns has many attributes useful for your tasks. In particular,
sys._getframe(1).f_code.co_name should be 'bar' as you require,
and sys._getframe(1).f_globals['__name__'] should be the module
name which you desire.
Alex