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# Circle Hell

Hi all,

I am new to Tk, so please bear with me. I need someone better at math
than me to help me figure this out. I am drawing multiple arcs on the
same circle. All arcs start at 90 and have varying negative extents
(different colors, goes all the way around. Represents a microbial
genome). So now that my arcs are drawn, I would would like to draw a
line, 25 pixels long that starts on the circle at the endpoint of each
of the arcs, and looks like an extension of the radius extending above
the circle. Then I would like to print text at the end of this line. So
my question is how do I dynamically calculate the line coordinates?
Circle size is fixed, number of arcs and their extents are variable.

Code for drawing arc;
\$x1,\$y1 = 25
\$x2,\$y2 = 775
\$xcenter = \$x2/2 + \$x1;
\$ycenter = \$y2/2 + \$y1;

\$canvas->createArc(\$x1,\$y1,\$x2,\$y2,
-width=>10,
-outline=>\$colors[\$color],
-style=>'arc',
-start=>90,
-extent=>-\$actual_angle,
-tags=>\$myorfs{\$key});

What I have so far to draw lines:

\$canvas->createLine(\$xstart+\$xcenter,
\$ystart+\$ycenter,
\$xstart+(\$xstart*0.01)+\$xcenter,
\$ystart+(\$ystart*0.01)+\$ycenter);

This draws an oval of lines, inside the orginal circle, with the line
length having sin periodicity around the circle. Can anyone improve my
math so that I can get the lines placed properly with the proper length?

Please email me directly as well as respond to the list. Thanks so much

--Math Challenged Mark

Ma**********@bayer.com
Jul 18 '05 #1
2 1973 On Thu, 04 Sep 2003 07:55:18 -0700, Talon <ta*****@hotmail.com> (by way of Talon <ta*****@hotmail.com>) wrote:
Hi all,

I am new to Tk, so please bear with me. I need someone better at math
than me to help me figure this out. I am drawing multiple arcs on the
same circle. All arcs start at 90 and have varying negative extents
(different colors, goes all the way around. Represents a microbial
genome). So now that my arcs are drawn, I would would like to draw a
line, 25 pixels long that starts on the circle at the endpoint of each
of the arcs, and looks like an extension of the radius extending above
the circle. Then I would like to print text at the end of this line. So
my question is how do I dynamically calculate the line coordinates?
Circle size is fixed, number of arcs and their extents are variable.

Code for drawing arc;
\$x1,\$y1 = 25
\$x2,\$y2 = 775
\$xcenter = \$x2/2 + \$x1;
\$ycenter = \$y2/2 + \$y1;

\$canvas->createArc(\$x1,\$y1,\$x2,\$y2,
-width=>10,
-outline=>\$colors[\$color],
-style=>'arc',
-start=>90,
-extent=>-\$actual_angle,
-tags=>\$myorfs{\$key});

What I have so far to draw lines:

\$ystart = (sin(\$current_arclength)*\$radius+\$ycenter) /10; These look ok except dividing by 10, assuming the units for the angle are ok (degrees vs radians?)
Dividing by 10 seems weird here, so try leaving it out.
\$canvas->createLine(\$xstart+\$xcenter,
\$ystart+\$ycenter, From above, xstart already has xcenter in it, so don't add it again. Same for ycenter. \$xstart+(\$xstart*0.01)+\$xcenter,
\$ystart+(\$ystart*0.01)+\$ycenter); If you want to draw a 25-pixel line, where is the "25"? You just need to resolve the 25
into x and y components and add them to your respective starting points, I would think.
So UIAM the above becomes (giving a name to the 25-pixel length (assuming dimensions are in pixels)

\$tick_length = 25.0;

\$canvas->createLine(\$xstart,
\$ystart,
\$xstart+ cos(\$current_arclength)*\$tick_length,
\$ystart+ sin(\$current_arclength)*\$tick_length);

This draws an oval of lines, inside the orginal circle, with the line
length having sin periodicity around the circle. Can anyone improve my
math so that I can get the lines placed properly with the proper length?

Please email me directly as well as respond to the list. Thanks so much

--Math Challenged Mark

Ma**********@bayer.com

HTH

Regards,
Bengt Richter
Jul 18 '05 #2

I wouldn't be using lengths of arcs, if I were you. And that division
by 10 looks a bit odd, too.

Given a circle of radius r, if the arc stops at an angle theta to the
horizontal (measured anticlockwise from the east), then the point on
the circle is:
x = xcentre + r * cos(theta)
y = ycentre + r * sin(theta)

If you want to know the point at a distance 25 from the circle, simply
substitute (r + 25) in the formula above.
Jul 18 '05 #3

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