WIWA wrote:
I'm trying to write the following in python:
j=0
for i in range(len(datumlijst)+1):
if (datumlijst[i+1]!=datumlijst):
datum[j]=datumlijst
j=j+1
print datum[:]
it complains about the part: datumlijst[i+1]!=datumlijst
You are comparing a list with a list entry which is probably unintended.
datum[j]=datumlijst
IndexError: list assignment index out of range
You seem to assume that a list grows automatically. That's not true in
Python.
Now here's my guess of your intentions:
datumlijst = [1,1,2,2,3,4,5,5,5,5,6,3]
datumlijst.sort()
datum = [datumlijst[0]]
for i in range(len(datumlijst)-1): # all list indexes start with 0
if datumlijst[i+1] != datumlijst[i]: # both indexed
datum.append(datumlijst[i+1]) # note the append()
print datum #no need for [:]
There may still sit a bug in the above. The following should be a little
more robust, e. g. no need to sort datumlijst, no extensive use of list
indexes:
from sets import Set
datumlijst = [1,1,2,2,3,4,5,5,5,5,6,3]
print list(Set(datumlijst))
This is Python 2.3 only, in 2.2 you can do it with a dictionary, using the
keys only.
Peter
PS: I see you've already fallen in love with whitespace :-)
