bsddb.btopen()

[Anthony McDonald]

PythonWin 2.3 (#46, Jul 29 2003, 18:54:32) [MSC v.1200 32 bit (Intel)] on
win32.
Portions Copyright 1994-2001 Mark Hammond (mh******@skippinet.com.au) - see
'Help/About PythonWin' for further copyright information.

import os
import bsddb
os.chdir("c:/test")
my_data = bsddb.btopen("testing", 'c')
for i in range(10): .... if i == 5:
.... pass
.... else:
.... my_data['%d'%i] = '%d'% (i*i)
.... my_data.keys() ['0', '1', '2', '3', '4', '6', '7', '8', '9'] my_data.sync()
Now heres where my problem is.

The documentation explicitly states that a btopen database when asked to
locate a key that doesn't exist in the dataset, will return the next sorted
key from the dataset.

So my_data.set_location('5') should return as if I'd called
my_data.set_location('6') my_data.set_location('5') Traceback (most recent call last):
File "<interactive input>", line 1, in ?
File "C:\Python23\lib\bsddb\__init__.py", line 117, in set_location
return self.dbc.set(key)
DBNotFoundError: (-30991, 'DB_NOTFOUND: No matching key/data pair found')

Okay maybe it has positioned the cursor, but is just raising the exception
to politely tell me that I'm not pointing at the key I asked for. So
my_data.previous() will return the key/data pair for key "4".
my_data.previous()

('9', '81')

Okay its pointing at the end of the database. Erm thats not as advertised.

Okay whats broken? Is the documentation wrong? Is my version of Python
wrong?, or do I need to drink some more coffee?

TonyM