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itertools.take?

Is there any interest in adding a "Haskellish" take function to
itertools? I know its easy enough to roll my own, I've been using:

take = lambda iter, n: [x for x in itertools.islice(iter, 0, n)]

which works, but I was wondering if it was common enough to get into
itertools?

-Dan

Jul 18 '05 #1
1 2180

"Dan Williams" <da*@osheim.org> wrote in message
news:vh************@corp.supernews.com...
Is there any interest in adding a "Haskellish" take function to
itertools? I know its easy enough to roll my own, I've been using:

take = lambda iter, n: [x for x in itertools.islice(iter, 0, n)]
I use:
def take(n, seq):

.... return list(islice(seq, n))

which works, but I was wondering if it was common enough to get into
itertools?


It made it to the lastest update of the examples in the docs for itertools.
If there is enough demand, it could go into Py2.4
Raymond Hettinger
Jul 18 '05 #2

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