why does ''.join(lst)
not automatically do
''.join([str(i) for i in lst])
? That is, is there ever a time when one does not want .join to make
everything into a string? This seems like reasonable default behavior, but
maybe I'm missing something?
-doug 3  2907 
"drs" <dr*@ecp.cc> wrote in message
news:eo********************@newssrv26.news.prodigy .com... why does
''.join(lst)
not automatically do
''.join([str(i) for i in lst])
? That is, is there ever a time when one does not want .join to
make everything into a string? This seems like reasonable default
behavior, but maybe I'm missing something?
If the members of lst are already str strings, this would be a waste
of time. If they are unicode strings, this would be the wrong thing
to do. Auto conversions are not Python's style.
Terry J. Reedy
I would risk a guess that this comes under the "explicit is better than
implicit" guideline.
''.join([str(i) for i in lst])
Explains to everyone that you know the list has some non-string things,
and you intend them to be str()'ified.
Intention-guessingly yours,
Simon.
"drs" <dr*@ecp.cc> wrote in
news:eo********************@newssrv26.news.prodigy .com: why does
''.join(lst)
not automatically do
''.join([str(i) for i in lst])
? That is, is there ever a time when one does not want .join to make
everything into a string? This seems like reasonable default
behavior, but maybe I'm missing something?
-doug
"Terry Reedy" <tj*****@udel.edu> wrote in message
news:Q4********************@comcast.com...
"drs" <dr*@ecp.cc> wrote in message
news:eo********************@newssrv26.news.prodigy .com... why does
>> ''.join(lst)
not automatically do
>> ''.join([str(i) for i in lst])
? That is, is there ever a time when one does not want .join to
make everything into a string? This seems like reasonable default
behavior, but maybe I'm missing something?
If the members of lst are already str strings, this would be a waste
of time. If they are unicode strings, this would be the wrong thing
to do. Auto conversions are not Python's style.
l = [u'abcde', 'fghij']
''.join(l)
u'abcdefghij'
this seems to be auto converting the non-unicode to unicode?
-d This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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