Can Anyone Help me on this

blah

i m trying to reverse the order in which the
strings are stored in list

then pop it into another list

what m i doin worng??

here's the code:

list1 = []
list2 = []
list1.extend('123456789')

print list1

for a in list1:
list2 = list1.pop()

print list2
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Nov 3 '05 #1

jmdeschamps

bl**@blah.blah wrote:

i m trying to reverse the order in which the
strings are stored in list

then pop it into another list

what m i doin worng??

here's the code:

list1 = []
list2 = []
list1.extend('123456789')

print list1

for a in list1:
list2 = list1.pop()

print list2
--
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* http://www.newsleecher.com/?usenet

well, mant things are happening, so many it's not clear to me what
you're trying to do...
BUT, considering your for statement, since you are poping elements out
of list you are shortening it, so you are only getting as far as
element '5'

If what you want is a reversed copy, you could just append list1
elements to list2, and use the reverse function such as

...
for i in list1: .... list2.append(i)
.... list2.reverse()
list1 ['1', '2', '3', '4', '5', '6', '7', '8', '9'] list2

['9', '8', '7', '6', '5', '4', '3', '2', '1']

Nov 3 '05 #2

Cyril Bazin

Here is an example of copying then reversing a list:

l1 = [1,2,"C"]
l2 = l1[:]
l2.reverse()
l2

['C', 2, 1]

Nov 3 '05 #3

David Wahler

jm*********@gmail.com wrote:

If what you want is a reversed copy, you could just append list1
elements to list2, and use the reverse function such as

...
for i in list1: ... list2.append(i)
... list2.reverse()
list1 ['1', '2', '3', '4', '5', '6', '7', '8', '9'] list2 ['9', '8', '7', '6', '5', '4', '3', '2', '1']

It's much clearer and simpler to just do:

list2 = list1[:]
list2.reverse()

This saves all the messing around with append, and has the advantage
that it runs faster (by a factor of 30, on my computer).

-- David

Nov 3 '05 #4

Mike Meyer

jm*********@gmail.com writes:

If what you want is a reversed copy, you could just append list1
elements to list2, and use the reverse function such as

...
for i in list1: ... list2.append(i)
...

Don't do this by ahnd - let python do it for you:

list2 = list(list1)

or

list2 = list1[:]

<mike

list2.reverse()
list1 ['1', '2', '3', '4', '5', '6', '7', '8', '9'] list2

['9', '8', '7', '6', '5', '4', '3', '2', '1']

--
Mike Meyer <mw*@mired.org> http://www.mired.org/home/mwm/
Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information.

Nov 3 '05 #5

jmdeschamps

....
list2=list1[:]
....
Yes, naturally, where was my head ?-))

Nov 3 '05 #6

Peter Hansen

bl**@blah.blah wrote:

i m trying to reverse the order in which the
strings are stored in list

then pop it into another list

what m i doin worng??

here's the code:

list1 = []
list2 = []
list1.extend('123456789')

How about this instead (Python 2.4 or later):

list2 = list(reversed('123456789'))

-Peter

Nov 3 '05 #7

blah

Thanks Guys, Wow, i didnt knew that there was alist reverse function.
thx. also. i need a good documentation of the os and sys modules as
well as builtin functions of python.

the standard python documentation doesnt work for me. can u recommend
something?
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Nov 4 '05 #8

Alex Martelli

bl**@blah.blah <blahman> wrote:

Thanks Guys, Wow, i didnt knew that there was alist reverse function.
thx. also. i need a good documentation of the os and sys modules as
well as builtin functions of python.

the standard python documentation doesnt work for me. can u recommend
something?

I'm biased, but I'd recommend the book "Python in a Nutshell". My
suggestion: take advantage of the "Safari" online library for 2 weeks'
of free subscription -- make sure you cancel after 13 days if you want
to avoid being billed for the subscription's fee. In those 2 weeks you
get to read for free a few books in the online library -- I'd suggest
sampling the Nutshell, the Cookbook and possibly a couple more...
Alex

Nov 4 '05 #9

blah

Thx Alex.
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Nov 4 '05 #10