Hi!
I must be blind because I didn't find anything in the documentation
which says iterating over an dictionary iterates over its keys.
For example
a_dictionary = {0: "zero", 1: "one"}
for x in a:
print x
gives you
0
1
Where is this information hidden? :)
Bye,
Dennis 2 1407
Dennis Benzinger wrote: I must be blind because I didn't find anything in the documentation which says iterating over an dictionary iterates over its keys.
For example
a_dictionary = {0: "zero", 1: "one"} for x in a: print x
gives you
0 1
Where is this information hidden? :)
You should examine your program. Simply pasting the code above to the
Python shell fails as expected:
$ python
Python 2.4.2 (#1, Oct 1 2005, 14:32:09)
[GCC 3.3.5 20050117 (prerelease) (SUSE Linux)] on linux2
Type "help", "copyright", "credits" or "license" for more information. a_dictionary = {0: "zero", 1: "one"} for x in a:
.... print x
....
Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'a' is not defined
Ciao, Michael.
On Tue, 25 Oct 2005 18:02:47 +0200, Michael Ströder wrote: Dennis Benzinger wrote: I must be blind because I didn't find anything in the documentation which says iterating over an dictionary iterates over its keys.
[snip] Where is this information hidden? :)
You should examine your program. Simply pasting the code above to the Python shell fails as expected:
Yes, this is true, but also irrelevant. The question isn't about the code,
but about the documentation.
The answer does appear to be hidden quite deeply. I had to dig out an old
"What's New" for version 2.2 to find it, hidden away in a section on
iterators: http://aspn.activestate.com/ASPN/doc...00000000000000
--
Steven. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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