How to retrieve the filename of a module

[mku]

Hi,

there´s a function inside a module. How can these function retrieve
the path+name of his module ? (The path is most important).
That should also work if the module is part of a package.

Thanks in advance

Martin

[Lawrence Oluyede]

Il 2005-10-20, mku <ma**********@thomson.net> ha scritto:

Hi,

there´s a function inside a module. How can these function retrieve
the path+name of his module ? (The path is most important).
That should also work if the module is part of a package.

rhymes@voodoo:~ $ cat > test.py
print __file__
import os
print os.path.abspath(__file__)

rhymes@voodoo:~ $ python test.py
test.py
/home/rhymes/test.py

Bye

--
Lawrence
http://www.oluyede.org/blog

[Jim O'D]

mku wrote:

Hi,

there´s a function inside a module. How can these function retrieve
the path+name of his module ? (The path is most important).
That should also work if the module is part of a package.

Thanks in advance

Martin

Try the following in the function:

import traceback
f = traceback.extract_stack(limit=2)

If you output f to the interpreter, you'll see the filename but I don't
know what position in the output list it is guaranteed to be.

Jim

[Lawrence Oluyede]

Il 2005-10-20, Lawrence Oluyede <ra***@dot.com> ha scritto:

Il 2005-10-20, mku <ma**********@thomson.net> ha scritto:

Hi,

there´s a function inside a module. How can these function retrieve
the path+name of his module ? (The path is most important).
That should also work if the module is part of a package.

rhymes@voodoo:~ $ cat > test.py
print __file__
import os
print os.path.abspath(__file__)

rhymes@voodoo:~ $ python test.py
test.py
/home/rhymes/test.py

Also __name__ for the name of the module

--
Lawrence
http://www.oluyede.org/blog