d = {}
for x in [1,2,3]: .... d[x] = lambda y: y*x
.... d[1](3)
9
Because x in the lambda definition isn't evaluated until the lambda is
executed, at which point x is 3.
Is there a way to specifically hard code into that lambda definition the
contemporary value of an external variable? In other words, is there a
way to rewrite the line "d[x] = lambda y: y*x" so that it is always the
case that d[1](3) = 3?
Thanks!
-jag