Quick help needed: how to format an integer ?

[durumdara]

Hi !

I need to convert some integer values.

"1622" ->"1 622"

or

"10001234" -> ""10.001.234""

So I need thousand separators.

Can anyone helps me with a simply solution (like %xxx) ?

Thanx for it: dd

Ps:
Now I use this proc:

def toths(i):
s=str(i)
l=[]
ls=len(s)
for i in range(ls):
c=s[ls-i-1]
if i%3==0 and i<>0:
c=c+"."
l.append(c)
l.reverse()
return "".join(l)

[Diez B. Roggisch]

du*******@mailpont.hu wrote:

Hi !

I need to convert some integer values.

"1622" ->"1 622"

or

"10001234" -> ""10.001.234""

So I need thousand separators.

Can anyone helps me with a simply solution (like %xxx) ?

The module locale does what you need, look at ist docs, especially
locale.str
locale.format
Regards,

Diez

[Paul Rubin]

"du*******@mailpont.hu" <du*******@mailpont.hu> writes:

"10001234" -> ""10.001.234""
So I need thousand separators.
Can anyone helps me with a simply solution (like %xxx) ?

I think you're supposed to do a locale-specific conversion (I've never
understood that stuff). You could also do something like this:

def f(n): if n < 0: return '-' + f(-n)
if n < 1000: return '%d' % n
return f(n//1000) + '.' + '%03d' % (n%1000)
f(39009000900909090000009) '39.009.000.900.909.090.000.009' f(39802183) '39.802.183' f(3008) '3.008' f(0) '0' f(-9898239839) '-9.898.239.839' f(12345)

'12.345'