re.search experts needed on fqdn stripping..

[rh0dium]

Hi all,

Ok I have a list

hosts = [ "poundcake.fqdn.com", "scorpion.fqdn.com", "loghost",
"scorpian", "localhost", "lan", "lan.fpdn.com" ]

Assumptions:
scorpian.fqdn.com == scorpian
lan == lan.fqdn.com

I want pear this list down based on the following:
1. ignore loghost, localhost, timehost, mailhost
2. Use the first found name used reguardless if it is the fqdn or not

So what you would get back out is this..

hosts = [ "poundcake.fqdn.com", "scorpion.fqdn.com", "lan" ]

Now here is my code - and I have a problem with the splitting. I am
really looking for a cool ( but understandable ) way to simplify this..

e =[]
for host in hosts:

sn = re.split( "\.", host)

ig = 1
ignore = [ "localhost", "loghost", "timehost", "mailhost" ]
for i in ignore:
if i == sn[0]:
ig = 0
if ig:
print "%s not ignored" % sn[0]
found = 0
for n in e:
sm = re.split( "\.", n)
print "checking %s to %s" % (sm[0], sn[0])
if sm[0] == sn[0]:
print "match";
found = 1
if found == 0:
print "appending %s " % host
e.append(host)

print e
Which kicks out..
poundcake not ignored
appending poundcake.nsc.com
scorpion not ignored
checking poundcake to scorpion
appending scorpion.nsc.com
scorpian not ignored
checking poundcake to scorpian
checking scorpion to scorpian
appending scorpian
lan not ignored
checking poundcake to lan
checking scorpion to lan
checking scorpian to lan
appending lan
['poundcake.fpdn.com', 'scorpion.fpdn.com', 'scorpian', 'lan']

Crap still wrong..

[rh0dium]

OK Duh..

After thinking about it for a bit longer i simplified it but still have
the same problem..

e =[]
hosts = [ "poundcake.fpdn.com", "scorpion.fpdn.com", "loghost",
"scorpian", "localhost", "lan" ]

ignore = [ "localhost", "loghost", "timehost", "mailhost" ]

for host in hosts:
sn = re.split( "\.", host)
if not sn[0] in ignore:
e.append(host)
ignore.append(sn[0])
print e

But this STILL gives me some problems..
['poundcake.nsc.com', 'scorpion.fqdn.com', 'scorpian', 'lan']

Nope - OK I am an idiot - try spelling idiot..

Thanks

rh0dium wrote:

Hi all,

Ok I have a list

hosts = [ "poundcake.fqdn.com", "scorpion.fqdn.com", "loghost",
"scorpian", "localhost", "lan", "lan.fpdn.com" ]

Assumptions:
scorpian.fqdn.com == scorpian
lan == lan.fqdn.com

I want pear this list down based on the following:
1. ignore loghost, localhost, timehost, mailhost
2. Use the first found name used reguardless if it is the fqdn or not

So what you would get back out is this..

hosts = [ "poundcake.fqdn.com", "scorpion.fqdn.com", "lan" ]

Now here is my code - and I have a problem with the splitting. I am
really looking for a cool ( but understandable ) way to simplify this..

e =[]
for host in hosts:

sn = re.split( "\.", host)

ig = 1
ignore = [ "localhost", "loghost", "timehost", "mailhost" ]
for i in ignore:
if i == sn[0]:
ig = 0
if ig:
print "%s not ignored" % sn[0]
found = 0
for n in e:
sm = re.split( "\.", n)
print "checking %s to %s" % (sm[0], sn[0])
if sm[0] == sn[0]:
print "match";
found = 1
if found == 0:
print "appending %s " % host
e.append(host)

print e
Which kicks out..
poundcake not ignored
appending poundcake.nsc.com
scorpion not ignored
checking poundcake to scorpion
appending scorpion.nsc.com
scorpian not ignored
checking poundcake to scorpian
checking scorpion to scorpian
appending scorpian
lan not ignored
checking poundcake to lan
checking scorpion to lan
checking scorpian to lan
appending lan
['poundcake.fpdn.com', 'scorpion.fpdn.com', 'scorpian', 'lan']

Crap still wrong.

[Mike Meyer]

"rh0dium" <sk****@pointcircle.com> writes:

After thinking about it for a bit longer i simplified it but still have
the same problem..

e =[]
hosts = [ "poundcake.fpdn.com", "scorpion.fpdn.com", "loghost",
"scorpian", "localhost", "lan" ]

ignore = [ "localhost", "loghost", "timehost", "mailhost" ]

for host in hosts:
sn = re.split( "\.", host)
This should be host.split(".").
if not sn[0] in ignore:
e.append(host)
ignore.append(sn[0])
print e

But this STILL gives me some problems..
['poundcake.nsc.com', 'scorpion.fqdn.com', 'scorpian', 'lan']

Nope - OK I am an idiot - try spelling idiot..

Can I take it that you saw that "scorpion" is not the same as
"scorpian"?

BTW, if you're using 2.4 and don't care about portability, I'd make
ignore a set instead of a list.

<mike
--
Mike Meyer <mw*@mired.org> http://www.mired.org/home/mwm/
Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information.