Hi, on Linux (Fedora FC4) and Python 2.4.1
I am trying to know the time delta in seconds between two times given
in the HHMMSS format. My code looks like:
import datetime, time
ta1=(time.strptime('000001', '%H%M%S'))
ta2=(time.strptime('230344', '%H%M%S'))
t1=time.mktime(ta1)
t2=time.mktime(ta2)
print t1, t2
-2147483648.0 -2147483648.0
I just can not figure out, why the t1 and t2 are the same?
Thanks for your comments
Petr Jakes 4 10227
I don't get the same results: import datetime, time ta1=(time.strptime('000001', '%H%M%S')) ta2=(time.strptime('230344', '%H%M%S')) t1=time.mktime(ta1) t2=time.mktime(ta2) print t1, t2
-2208988799.0 -2208905776.0 print t1-t2
-83023.0
Suse 9.3, python 2.4 (all 64bit)
Matt
--
| Matt Hammond
| R&D Engineer, BBC Research and Development, Tadworth, Surrey, UK.
"McBooCzech" <pe**@tpc.cz> writes: Hi, on Linux (Fedora FC4) and Python 2.4.1 I am trying to know the time delta in seconds between two times given in the HHMMSS format. My code looks like:
import datetime, time ta1=(time.strptime('000001', '%H%M%S')) ta2=(time.strptime('230344', '%H%M%S')) t1=time.mktime(ta1) t2=time.mktime(ta2) print t1, t2
-2147483648.0 -2147483648.0
I just can not figure out, why the t1 and t2 are the same?
Hm. You are trying to convert (1900, 1, 1, 0, 0, 1, 0, 1, -1) to epoch.
However, epochs start from 1970-01-01 00:00. So that at least is not right.
Hint... see what var ta1 is. With python2.3 you'll get overflow error, becuase
mktime argument is out of range.
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# Edvard Majakari Software Engineer
# PGP PUBLIC KEY available Soli Deo Gloria!
$_ = '456476617264204d616a616b6172692c20612043687269737 469616e20'; print
join('',map{chr hex}(split/(\w{2})/)),uc substr(crypt(60281449,'es'),2,4),"\n";
according to the Python documentation: http://docs.python.org/lib/module-time.html
===snip===
Values 100-1899 are always illegal.
..
..
strptime(string[, format])
..
..
The default values used to fill in any missing data are:
(1900, 1, 1, 0, 0, 0, 0, 1, -1)
===snip===
BTW, check the following code: import datetime, time print time.gmtime(time.mktime((1900, 1, 1, 0, 0, 0, 0, 1, -1)))
(1901, 12, 13, 20, 45, 52, 4, 347, 0)
but (1900, 1, 1, 0, 0, 0, 0, 1, -1) is (IMHO) expected.... Hmmm. But I
am just a newbie!!! :)
Anyway, maybe I am just using a wrong way how to calculate time delta
between two time values given in the format "HHMMSS".
Does Python provide some other ways how to calculate it?
Petr Jakes
"McBooCzech" <pe**@tpc.cz> writes: ===snip=== Values 100-1899 are always illegal. . . strptime(string[, format]) . . The default values used to fill in any missing data are: (1900, 1, 1, 0, 0, 0, 0, 1, -1) ===snip===
BTW, check the following code:import datetime, time print time.gmtime(time.mktime((1900, 1, 1, 0, 0, 0, 0, 1, -1))) (1901, 12, 13, 20, 45, 52, 4, 347, 0)
but (1900, 1, 1, 0, 0, 0, 0, 1, -1) is (IMHO) expected.... Hmmm. But I am just a newbie!!! :)
You are comparing apples and oranges here. You checked documentation of
strptime, and the problem is in the use of time.mktime().
The point: time.mktime() returns Epoch time (seconds since 1970) and you are
passing it a tuple which is (way before) 1970. There is no such thing as
negative epoch. It is like computing packaging day of milk which hasn't been
milked from the cow yet :)
I really wonder what version of Python you are running: import datetime, time print time.gmtime(time.mktime((1900, 1, 1, 0, 0, 0, 0, 1, -1)))
Traceback (most recent call last):
File "<stdin>", line 1, in ?
OverflowError: mktime argument out of range
Python 2.3 and 2.4 both give the same error. As for the python version 2.2, no
datetime module was implemented.
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# Edvard Majakari Software Engineer
# PGP PUBLIC KEY available Soli Deo Gloria!
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