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# new line

 P: n/a Dear friends I'm so sorry to bore you with this trivial problem. Allthou: I have string having 0x0a as new line, but I should have \n instead. How should I solve it? I've triedtext_new=tex_old.replace(str(0x0a), '\n') and other things, but none of them worked. Thanks in advance Aug 29 '05 #1
5 Replies

 P: n/a "Kuljo" schrieb im Newsbeitrag news:K1*******************@nntpserver.swip.net... Dear friends I'm so sorry to bore you with this trivial problem. Allthou: I have string having 0x0a as new line, but I should have \n instead. How should I solve it? I've triedtext_new=tex_old.replace(str(0x0a), '\n') and other things, but none of them worked. Thanks in advance text_new=tex_old.replace(chr(0x0a), '\r\n') works for me. Claudio P.S. str(0x0a) == '10' Aug 29 '05 #2

 P: n/a Kuljo wrote: Dear friends I'm so sorry to bore you with this trivial problem. Allthou: I have string having 0x0a as new line, but I should have \n instead. In [9]: '\x0a' Out[9]: '\n' They're the same thing. -- Robert Kern rk***@ucsd.edu "In the fields of hell where the grass grows high Are the graves of dreams allowed to die." -- Richard Harter Aug 29 '05 #3

 P: n/a Kuljo wrote: Dear friends I'm so sorry to bore you with this trivial problem. Allthou: I have string having 0x0a as new line, but I should have \n instead. How should I solve it? I've triedtext_new=tex_old.replace(str(0x0a), '\n') and other things, but none of them worked. Thanks in advance I have found this in the meantime: nl="\\"+"n"text_new=replace(text_old, chr(10), nl) It works. Aug 30 '05 #4

 P: n/a Kuljo wrote: Kuljo wrote:I'm so sorry to bore you with this trivial problem. Allthou: I have stringhaving 0x0a as new line, but I should have \n instead. I have found this in the meantime:nl="\\"+"n" Note: this is unnecessary. You could just do nl='\\n' instead, and you don't need the variable "nl" either, which by the way is confusingly named. Your variable "nl" is actually bound to the two character sequence \ followed by n instead of a "newline". Is that really what you wanted? text_new=replace(text_old, chr(10), nl) This use of replace() is deprecated. Use text_old.replace() instead. It works. For some definitions of "works". This only works if you wanted the *single* character represented by '\x0a' to turn into the *two* characters backslash-followed-by-letter-n. The following you might find instructive: old = 'some\x0atext' old 'some\ntext' print old some text old.encode('string-escape') 'some\\ntext' print old.encode('string-escape') some\ntext This will turn other control characters into their equivalent two-character escaped representation as well, such as \t and \r, as necessary. -Peter Aug 30 '05 #5

 P: n/a Kuljo wrote: Kuljo wrote: Dear friends I'm so sorry to bore you with this trivial problem. Allthou: I have string having 0x0a as new line, but I should have \n instead. How should I solve it? I've tried>text_new=tex_old.replace(str(0x0a), '\n') and other things, but none of them worked. Thanks in advance I have found this in the meantime:nl="\\"+"n"text_new=replace(text_old, chr(10), nl) It works. Thanks Peter, you are right, eventext_new=replace(text_old, chr(10), "\\n") works. Yes, it was exactly what I needed. The problem actually was: I'm using Pilot V for years and a part of my "knowledge base" is stored in den memo files. On the PC side I'm using jpilot (Linux Kubuntu 5.04) which works perfectly. Now I wanted to try out kontact (groupware). The shortcoming is that kontact (actually kpilot in the background) does not import the memos. But it store them in a folder as a file per memo. In this file are the cr/lf indicated by hex 0a. The notes in kontact uses char \n instead. For this translation I made a python script which works now. Kind regards Kuljo Aug 31 '05 #6

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