Finding # prefixing numbers

[peterbe]

In a text that contains references to numbers like this: #583 I want to
find them with a regular expression but I'm having problems with the
hash. Hopefully this code explains where I'm stuck:

import re
re.compile(r'\b(\d\d\d)\b').findall('#123 x (#234) or:#456 #6789') ['123', '234', '456'] re.compile(r'\b(X\d\d\d)\b').findall('X123 x (X234) or:X456 X6789') ['X123', 'X234', 'X456'] re.compile(r'\b(#\d\d\d)\b').findall('#123 x (#234) or:#456 #6789') [] re.compile(r'\b(\#\d\d\d)\b').findall('#123 x (#234) or:#456 #6789')

[]

As you can guess, I'm trying to find a hash followed by 3 digits word
bounded. As in the example above, it wouldn't have been a problem if
the prefix was an 'X' but that's not the case here.

[Duncan Booth]

pe*****@gmail.com wrote:

In a text that contains references to numbers like this: #583 I want
to find them with a regular expression but I'm having problems with
the hash. Hopefully this code explains where I'm stuck:

import re
re.compile(r'\b(\d\d\d)\b').findall('#123 x (#234) or:#456 #6789') ['123', '234', '456'] re.compile(r'\b(X\d\d\d)\b').findall('X123 x (X234) or:X456 X6789') ['X123', 'X234', 'X456'] re.compile(r'\b(#\d\d\d)\b').findall('#123 x (#234) or:#456 #6789') [] re.compile(r'\b(\#\d\d\d)\b').findall('#123 x (#234) or:#456
#6789') []

As you can guess, I'm trying to find a hash followed by 3 digits word
bounded. As in the example above, it wouldn't have been a problem if
the prefix was an 'X' but that's not the case here.


From the re documentation:
\b
Matches the empty string, but only at the beginning or end of a word.
A word is defined as a sequence of alphanumeric or underscore
characters, so the end of a word is indicated by whitespace or a
non-alphanumeric, non-underscore character. Note that \b is defined as
the boundary between \w and \ W, so the precise set of characters
deemed to be alphanumeric depends on the values of the UNICODE and
LOCALE flags. Inside a character range, \b represents the backspace
character, for compatibility with Python's string literals.

# is not a letter or digit, so \b# will match only if the # is directly
preceded by a letter or digit which isn't the case in any of your examples.
Use \B (which is the opposite of \b) instead:

re.compile(r'\B(#\d\d\d)\b').findall('#123 x (#234) or:#456 #6789')

['#123', '#234', '#456']

[peterbe]

Thank you! That solved my problem.

[Caleb Hattingh]

You really owe it to yourself to try the PyParsing package, if you have to
do this kind of thing with any frequency.

The syntactic difference between PyParsing and regular expressions is
greater than the syntactic difference between Python and C.

thx
Caleb

On Tue, 19 Jul 2005 13:35:02 +0200, pe*****@gmail.com <pe*****@gmail.com>
wrote:

In a text that contains references to numbers like this: #583 I want to
find them with a regular expression but I'm having problems with the
hash. Hopefully this code explains where I'm stuck:

import re
re.compile(r'\b(\d\d\d)\b').findall('#123 x (#234) or:#456 #6789') ['123', '234', '456'] re.compile(r'\b(X\d\d\d)\b').findall('X123 x (X234) or:X456 X6789') ['X123', 'X234', 'X456'] re.compile(r'\b(#\d\d\d)\b').findall('#123 x (#234) or:#456 #6789') [] re.compile(r'\b(\#\d\d\d)\b').findall('#123 x (#234) or:#456 #6789')

[]

As you can guess, I'm trying to find a hash followed by 3 digits word
bounded. As in the example above, it wouldn't have been a problem if
the prefix was an 'X' but that's not the case here.