Replacing last comma in 'C1, C2, C3' with 'and' so that it reads 'C1, C2 and C3'

[Ric Da Force]

Hi,

I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.

Regards and sorry for the newbie question,

Ric

[Wolfram Kraus]

Ric Da Force wrote:

Hi,

I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.

Regards and sorry for the newbie question,

Ric

Use rfind and slicing:

x = "C1, C2, C3"
x[:x.rfind(',')]+' and'+x[x.rfind(',')+1:]

'C1, C2 and C3'

HTH,
Wolfram

[Peter Otten]

Ric Da Force wrote:

I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.

" and".join("C1, C2, C3".rsplit(",", 1))

'C1, C2 and C3'

Peter

[Christoph Rackwitz]

foo = "C1, C2, C3"
foo = foo.split(", ") # ['C1', 'C2', 'C3']
foo = ", ".join(foo[:-1]) + " and " + foo[-1] # just slicing and
joining it

you can always look for something here:
http://docs.python.org/lib/lib.html
and there:
http://docs.python.org/ref/

if you want to know, what methods an object has, try this (i shortened
the output a bit):

foo = "C1, C2, C3"
dir(foo) ['__add__', '__doc__', ..., 'capitalize', 'center', 'count',
'decode','encode', 'endswith', 'expandtabs', 'find', 'index',
'isalnum', 'isalpha', 'isdigit', 'islower', 'isspace', 'istitle',
'isupper', 'join', 'ljust', 'lower', 'lstrip', 'replace', 'rfind',
'rindex', 'rjust', 'rsplit', 'rstrip', 'split', 'splitlines',
'startswith', 'strip', 'swapcase', 'title', 'translate', 'upper',
'zfill']

[Brian van den Broek]

Ric Da Force said unto the world upon 12/07/2005 02:43:

Hi,

I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.

Regards and sorry for the newbie question,

Ric

Hi Ric,

the rsplit method of strings should get you going:

data = "the first bit, then the second, finally the third"
chunks = data.rsplit(',', 1)
chunks ['the first bit, then the second', ' finally the third']

Best,

Brian vdB

[Ric Da Force]

Hi guys,

Thank you all for your input! It was good to see so much convergence in the
approach! Again, I think that it speaks loudly for the concise way of doing
thins in Python... Anyway, I have typed in all of the solutions and have
gained a great understanding of how to do this in future.

Thanks again!

Ric
"Brian van den Broek" <bv****@po-box.mcgill.ca> wrote in message
news:ma***************************************@pyt hon.org...

Ric Da Force said unto the world upon 12/07/2005 02:43:

Hi,

I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so
that it reads:
'C1, C2 and C3' regardless of the length of the string.

Regards and sorry for the newbie question,

Ric

Hi Ric,

the rsplit method of strings should get you going:

data = "the first bit, then the second, finally the third"
chunks = data.rsplit(',', 1)
chunks ['the first bit, then the second', ' finally the third']

Best,

Brian vdB

[Bengt Richter]

On Wed, 13 Jul 2005 03:47:07 +0800, "Ric Da Force" <ri*@next-level.com.au> wrote:

Hi guys,

Thank you all for your input! It was good to see so much convergence in the
approach! Again, I think that it speaks loudly for the concise way of doing
thins in Python... Anyway, I have typed in all of the solutions and have
gained a great understanding of how to do this in future.

Thanks again!

Ric
"Brian van den Broek" <bv****@po-box.mcgill.ca> wrote in message
news:ma***************************************@py thon.org...

Ric Da Force said unto the world upon 12/07/2005 02:43:

Hi,

I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so
that it reads:
'C1, C2 and C3' regardless of the length of the string.

Regards and sorry for the newbie question,

Ric

Hi Ric,

the rsplit method of strings should get you going:

>>> data = "the first bit, then the second, finally the third"
>>> chunks = data.rsplit(',', 1)
>>> chunks

['the first bit, then the second', ' finally the third']

>>>

Best,

Brian vdB
Or, to finish Brian's solution by inserting the ", and" in place of the "," :

data = "the first bit, then the second, finally the third"
', and'.join(data.rsplit(',',1)) 'the first bit, then the second, and finally the third' ', and'.join('C1, C2, C3'.rsplit(',',1))

'C1, C2, and C3'

Regards,
Bengt Richter

[Alan Green]

Ric Da Force wrote:

Hi guys,

Thank you all for your input! It was good to see so much convergence in the
approach!

Just for divergence, you can also do this with regular expressions:

import re
re.sub("(.*),(.*)", r"\1 and\2", "C1, C2, C3")

'C1, C2 and C3'

Alan.

[Florian Diesch]

Ric Da Force <ri*@next-level.com.au> wrote:

I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.

import re
data = "the first bit, then the second, finally the third"
re.sub(r"(.*),", r"\1 and", data) 'the first bit, then the second and finally the third'

Florian
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