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Help: Trouble with imp.load_module

I'm not entirely sure what's going on here, but I suspect it's related
to my general lack of knowledge of the python import internals.

Here's the setup:

module: tester.py:
import imp
def loader(mname, mpath):
fp, pathname, description = imp.find_module (mname,[mpath])
m = imp.load_module (mname, fp, pathname, description)
if fp:
return m

module = loader("testA", "/path/to/testA/)
print module.test_fun c("/path/to/something")

module = loader("test.B" ,"/path/to/test.B/")
print module.test_fun c("/path/to/something")
module: testA.py:
def test_func(v):
import os
return os.path.exists( v)

module: test.B.py:
def test_func(v):
import os
return os.path.exists( v)
Okay, so modules "testA.py" and "test.B.py" are functionally identical,
except for the name of the module files themselves, and this is the
important part. The tester.py module is a really simple rig to run
"imp.load_modul e" on those two files.

You should get no problem running the first test of module "testA.py"
but you should get a traceback when attempting to run the second module
"test.B.py" :

Traceback (most recent call last):
File "tester.py" , line 15, in ?
print module.test_fun c("/path/to/something")
File "./test.B.py", line 2, in test_func
import os
File "/usr/lib/python2.4/os.py", line 131, in ?
from os.path import curdir, pardir, sep, pathsep, defpath, extsep,
ImportError: No module named path
So this must have something to do with the "." in the name of module
"test.B.py" but what is the problem, exactly? And how do I solve it? I
will sometimes need to run load_module on filenames which happen to have
"." in the name somewhere other than the ".py" extension. Is the
find_module somehow thinking this is a package?

Any help would be appreciated,

mediocre nebula.
Dec 11 '07 #1
0 2281

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