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Getting the start / end of string in regex through match objects

I want to get the start and end of all the patterns mattched in regex.
I know I can get it with start() and end() fn of matched objects. But
re.search() return the match object of first matching regex in the
string. I want all match objects in that string

Here is the string :

tmplstr = """

${list:parentls t}
an element ${elem:parentls t}

${list:childlst }
an element ${elem:childlst }

Here is the regex script:

# Compile List Patterns
# Start of List
lstpattern_st = r"(\$\{list: ([a-z]*[0-9 ]*)\})"
lstpat_st = re.compile(lstp attern_st)

# End of List
lstpattern_end = r"(\$\{/list:([a-z]*[0-9 ]*)\})"
lstpat_e = re.compile(lstp attern_end, re.I)
matchgrp_st = lstpat_st.searc h(tmplstr)
strt = matchgrp_st.sta rt()
print strt
matchgrp_e = lstpat_e.search (tmplstr)
end = matchgrp_e.end( )
print end
print self.tmplstr[strt:end]

I want all the start and end indices of the string but re.search()
returns the first regex met in the string. re.match() also wont work
because it search in the begining.

Can anyone help me in getting the start and end indices of all. OR can
provide any other solution instead of this

Jan 9 '06 #1
2 1716
"ankit" wrote:
I want to get the start and end of all the patterns mattched in regex.
I know I can get it with start() and end() fn of matched objects. But
re.search() return the match object of first matching regex in the
string. I want all match objects in that string

for m in re.finditer(pat tern, string):
print m.start(), m.end()

(or use the start offset to re.search)


Jan 9 '06 #2
Thanks frederik, :)

Jan 10 '06 #3

This thread has been closed and replies have been disabled. Please start a new discussion.

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