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split a directory string into a list

QUESTION:

How do I split a directory string into a list in Python, eg.

'/foo/bar/beer/sex/cigarettes/drugs/alcohol/'

becomes

['foo','bar','be er','sex','ciga rettes','drugs' ,'alcohol']

I was looking at the os.path.split command, but it only seems to
separate the filename from the path (or am I just using it wrong?). I
don't want to do it manually if I can help it, as there will have to be
exceptions for the cases where there is (not) a trailing (leading)
slash, or escape sequences involving /. Is there a built in command for
this?

Jul 18 '05 #1
1 2857
po*********@yah oo.com wrote:
QUESTION:

How do I split a directory string into a list in Python, eg.

'/foo/bar/beer/sex/cigarettes/drugs/alcohol/'

becomes

['foo','bar','be er','sex','ciga rettes','drugs' ,'alcohol']
'/foo/bar/beer/sex/cigarettes/drugs/alcohol/'.strip('/').split('/')

['foo', 'bar', 'beer', 'sex', 'cigarettes', 'drugs', 'alcohol']

Kent
I was looking at the os.path.split command, but it only seems to
separate the filename from the path (or am I just using it wrong?). I
don't want to do it manually if I can help it, as there will have to be
exceptions for the cases where there is (not) a trailing (leading)
slash, or escape sequences involving /. Is there a built in command for
this?

Jul 18 '05 #2

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