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redirecting stderr

Maybe it is something obvious, but what is going on with this code?

import sys
myerr = file("myerr.txt ", "w")
sys.stderr = myerr
try:
raise Exception, "some error"
finally:
myerr.close()
sys.stderr = sys.__stderr__

I would expect the error message to be written into "myerr.txt" , instead
it is displayed on the console, on regular stderr (?) and "myerr.txt" is
empty. I guess I misunderstood something ...

Michele Simionato
Jul 18 '05 #1
2 1443
Michele Simionato wrote:
Maybe it is something obvious, but what is going on with this code?

import sys
myerr = file("myerr.txt ", "w")
sys.stderr = myerr
try:
raise Exception, "some error"
finally:
myerr.close()
sys.stderr = sys.__stderr__

I would expect the error message to be written into "myerr.txt" , instead
it is displayed on the console, on regular stderr (?) and "myerr.txt" is
empty. I guess I misunderstood something ...

Michele Simionato


Hi,

os.close(2)
os.dup2(myerr.f ileno(), 2)

Works, but is dirty ...

HtH, Roland
Jul 18 '05 #2
Michele Simionato wrote:
Maybe it is something obvious, but what is going on with this code?

import sys
myerr = file("myerr.txt ", "w")
sys.stderr = myerr
try:
raise Exception, "some error"
finally:
myerr.close()
sys.stderr = sys.__stderr__

I would expect the error message to be written into "myerr.txt" , instead
it is displayed on the console, on regular stderr (?) and "myerr.txt" is
empty. I guess I misunderstood something ...


I'd say you have to handle the exception before the original stderr is
restored, e. g:

import sys
import traceback
myerr = file("myerr.txt ", "w")
sys.stderr = myerr
try:
try:
raise Exception("some error")
except:
traceback.print _exc()
finally:
myerr.close()
sys.stderr = sys.__stderr__

As print_exc() allows you to specify a file parameter, you could of course
entirely drop the try ... finally.

Peter

Jul 18 '05 #3

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