Substring RegExp Extract path

[Nick]

Hi,

I'm trying to extract element of a directory path stored in the db with substring

"/help/support/index/time.jsp"

and i want to extract the 1st, 2nd and 3rd parts

1st = help, 2nd = support, 3rd = index

but I can't get the regular expressions correct.

Any ideas on what I need to do.

select substring(data,'????') from paths

TIA

[Joe Conway]

Nick wrote:

"/help/support/index/time.jsp"

and i want to extract the 1st, 2nd and 3rd parts

1st = help, 2nd = support, 3rd = index

Are you using 7.4? If so:

select split_part('/help/support/index/time.jsp','/',2),
split_part('/help/support/index/time.jsp','/',3),
split_part('/help/support/index/time.jsp','/',4),
split_part('/help/support/index/time.jsp','/',5);
split_part | split_part | split_part | split_part
------------+------------+------------+------------
help | support | index | time.jsp
(1 row)

See:
http://www.postgresql.org/docs/curre...ns-string.html

On Postgres 8.0.0beta1 you could also do:

select s.f[2], s.f[3], s.f[4]
from (select string_to_array('/help/support/index/time.jsp','/') as f)
as s;
f | f | f
------+---------+-------
help | support | index
(1 row)

HTH,

Joe

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