Notice: Trying to get property of non-object on execution of my code.

[haishk]

i have a php script for notifications, where i faced a problem with the non-object execution. i tried lot of googling but couldn't able to solve it out..

my code as follows::

<?php 
                                $sql = "SELECT * FROM input WHERE id =".$_GET["id"]; 
                                $result = mysqli_query ($conn,$sql);
 
                                if ($result-> num_rows > 0) { 
 
                                while($row -> $result->fetch_assoc()) { 
 
 
                                $myid = $row["id"] ;
 
                                $sql2 = "SELECT * FROM output WHERE question_id = $myid ORDER BY date DESC";
                                $result2 = $conn->query($sql2);
 
                                $sql3 = "SELECT COUNT(*) as rowCount FROM output WHERE question_id = '".$myid."'";
                                $result3 = $conn->query($sql3);
                                $rowCount= $result3->fetch_assoc();
                            ?>

and the error show it on if ($result-> num_rows > 0) { ..

Any suggestions are appreicited..

[Dormilich]

Any suggestions are appreicited..

your query failed. it's as simple as that.