Hi everyone, i have been working on this for hours but i can't solve the problem myself. Hope someone can help me out.
So i have a main page with has a search function -
<?php
-
$search = $_GET['search'];
-
$terms = explode(" ", $search);
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$query = "SELECT * FROM search WHERE ";
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foreach ($terms as $each){
-
$i++;
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if ($i == 1)
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$query .= "keywords LIKE '%$each%' ";
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else
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$query .= "OR keywords LIKE '%$each%' ";
-
}
-
-
$db = mysql_connect("a", "a", "a");
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mysql_select_db("a");
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mysql_query("SET NAMES UTF8", $db);
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$query = mysql_query($query);
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$numrows = mysql_num_rows($query);
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if ($numrows > 0) {
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while ($row = mysql_fetch_array($query)) {
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$id = $row['id'];
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$title = $row['title'];
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$description = $row['description'];
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$keywords = $row['keywords'];
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$link = $row['link'];
-
-
echo "<div id='kq' ><a href='http://bytes.com/a/rs.php?id=$id'>$title</a></div></br >";
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}
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}
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else
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echo "<div id='kq1'> '$search'</div>";
-
-
mysql_close ();
-
?>
-
as you can see, every result has link rs.php?id=$id specific to its id. Until now it's fine.
Then i create the rs.php -
<?php
-
$newid = (int) $_GET['id'];
-
-
$servername = "a";
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$username = "a";
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$password = "a";
-
-
$conn = new mysqli($servername, $username, $password);
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if ($conn->connect_error) {
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die("Connection failed: " . $conn->connect_error);
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}
-
-
mysql_select_db("a", $db);
-
-
$newid = (int) $_GET['id'];
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$result = mysql_query("SELECT * FROM 'search' WHERE id = 1", $db) ;
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$myrow = mysql_fetch_array($result);
-
-
-
echo $myrow["title"];
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mysql_close();
-
?> <html> <head> <meta charset='utf-8'> <title>dd</title> </head> <body> <?php echo $myrow['title']; ?> </body> </html>
-
When I click on the link of a result, no error found but the title doesn't appear. Ive been looking on this for hours, I found a same question on this website which was posted since 2007. Except the main page, our rs.php pages are exactly the same so i don't know mine doesn't work. Hope someone can help me out. Thank you...
8  1753 
On line 16, you're only looking for Id = 1
Yeah I forgot to change that back, I do that to test if there is any problem with the $newid=$_GET['id']; The original code: - $newid = (int) $_GET['id'];
-
$result = mysql_query("SELECT * FROM 'search' WHERE id = $newid", $db) ;
-
$myrow = mysql_fetch_array($result);
-
-
echo $newid;
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echo sdqsd;
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echo $myrow["title"];
-
mysql_close();
-
?>
-
-
<html>
-
<head>
-
<meta charset='utf-8'>
-
<title>dd</title>
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</head>
-
-
<body>
-
<?php echo $myrow['title']; ?>
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</body>
-
-
</html>
Still doesn't work though. I try
this time, apparently it's fine. It got the right id. But the title doesn't appear.
I also used - if ($conn->connect_error) {
-
die("Connection failed: " . $conn->connect_error);
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}
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echo "Connected successfully";
-
?>
The connection to database seems to be good too. hmmm Still working on this.
RonB 589
Expert Mod 512MB
Try dumping $myrow to see if it holds what you expect.
Change: - <?php echo $myrow['title']; ?>
To: - <?php print_r($myrow); ?>
or: - <?php var_dump($myrow); ?>
You should check that the table has
1) the id you're searching for
2) a field named title
3) the field is populated
yes It does. I checked that too. The id is int, auto_incr. the title is varchar limit 250 characters.the field is populated. hmmm.
With - <?php print_r($myrow['title']); ?>
nothing change . With - <?php var_dump($myrow['title']); ?>
i got the "NULL". hmm. I check id, title, ... everything was right but it still doesn't work ...
Thanks god, finally I work it out, thanks so much for your helps.
the problem was - $servername = "a";
-
$username = "a";
-
$password = "a";
-
-
$conn = new mysqli($servername, $username, $password);
-
if ($conn->connect_error) {
-
die("Connection failed: " . $conn->connect_error);
-
}
i changed it to - $db = mysql_connect("a", "a", "a");
and it worked ^_^. Im so happy, finally i can sleep well tonight.
Once again, thanks a lot for your helps :D
RonB 589
Expert Mod 512MB
You just took a step backwards. The mysql_ functions have been depreciated for some time and will removed from the next release.
You should be using mysqli_ or PDO.
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