comparison operator(output of the following program,and how it could be like that))

[gangabhavani]

<?php
$x='abcd';
$y=0;
if($x==$y){
echo "pass";}
else{
echo "fail";}
?>

[gangabhavani]

i have tried it the output is pass but am not getting how it could be "pass".... i was expecting the output could be fail since $x and $y are not equal ......but the output is pass how it comes???? can anyone help me????

[Rabbit]

It's because == is a loose comparison and will juggle data types. It will attempt to convert one data type to another before doing a comparison. In this case, the string is being parsed for a number, it finds no number, so it gets converted to the number 0. Hence, the pass.

If you want a strict comparison that compares values AND types, then you need to use ===.

More info can be found from the PHP manual here: http://www.php.net/manual/en/types.comparisons.php