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I am facing a small problem regarding this topic.I had write a code to autofill textboxes from database values when I type a id value in the previous textfield.i.e.if I type userid,the next textfields will autofill from database without refresh in ajax and php.my problem is that I cant find the error in my code.help me to find out.Here is my code: a.html - <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
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<html xmlns="http://www.w3.org/1999/xhtml">
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<head>
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<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
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<title>Untitled Document</title>
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<script type="text/javascript">
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var url = "getagentids.php?param=";
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function handleHttpResponse() {
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if (http.readyState == 4) {
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results = http.responseText.split(",");
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document.getElementById('agfn').value = results[0];
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document.getElementById('agsal').value = results[1];
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document.getElementById('agtel').value = results[2];
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document.getElementById('agid').value = results[3];
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}
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}
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function getagentids() {
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var idValue = document.getElementById("agid").value;
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var myRandom=parseInt(Math.random()*99999999); // cache buster
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http.open("GET", url + escape(idValue) + "&rand=" + myRandom, true);
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http.onreadystatechange = handleHttpResponse;
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http.send(null);
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}
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function getHTTPObject() {
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var xmlhttp;
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/*@cc_on
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@if (@_jscript_version >= 5)
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try {
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xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");
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} catch (e) {
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try {
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xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
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} catch (E) {
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xmlhttp = false;
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}
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}
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@else
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xmlhttp = false;
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@end @*/
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if (!xmlhttp && typeof XMLHttpRequest != 'undefined') {
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try {
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xmlhttp = new XMLHttpRequest();
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} catch (e) {
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xmlhttp = false;
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}
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}
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return xmlhttp;
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}
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var http = getHTTPObject(); // We create the HTTP Object
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</script>
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</head>
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<body>
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<form name="schform">
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<table>
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<tr>
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<td>Contact ID:</td>
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<td><input id="agid" type="text" name="contactid" onKeyUp="getagentids();"></td>
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</tr><tr>
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<td>Tel Number:</td> <td><input id="agtel" type="text" name="contacttel"></td>
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</tr><tr>
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<td>Name:</td> <td><input id="agfn" type="text" name="contactfullname"></td>
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</tr><tr>
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<td>Salutation:</td> <td><input id="agsal" type="text" name="contactsalutation"></td>
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</tr>
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<tr> <td><input type="reset" value="Clear"></td>
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<td></td>
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</tr>
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</table>
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</form>
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</body>
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</html>
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getagentids.php - <?php
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$link = mysql_connect('localhost', 'arbiocua_mita', 'asd123$');
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if (!$link)
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{
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die('Could not connect: ' . mysql_error());
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}
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mysql_select_db('arbiocua_monomita');
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//$param=intval($_GET['contactid']);
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if(strlen($param)>0)
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{
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$result = mysql_query("SELECT ContactFullName, ContactSalutation, ContactTel FROM contact WHERE ContactID LIKE '$param%'");
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if(mysql_num_rows($result)==1)
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{
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while($myrow = mysql_fetch_array($result))
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{
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$agentname = $myrow["ContactFullName"];
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$agenttel = $myrow["ContactTel"];
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$agentsal = $myrow["ContactSalutation"];
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$agentid = $myrow["ContactID"];
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$textout = $agentname.",".$agentsal.",".$agenttel.",".$agentid;
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} }
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else { $textout=" , , ,".$param;
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} }
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echo $textout;
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?>
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**database**:
table name 'contact'
ContactID ContactFullName ContactSalutation ContactTel
1  3722 
Just saying something doesn't work gives no helpful information. You need to describe what isn't working, what debugging steps you took, the results of those steps, and any error messages you received.
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