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How to make autopost back for 2 buttons on same page using php

In php page i have 2 buttons 1st button is for retrieving data from db and 2nd button also is for retrieving data from db in execution when i pressed 1st button its showing data and at the same time when i pressed 2nd button its showing data but same time the page losing 1st button data .i want to be displayed both button data at same time can any one help me please?????????????????????








Expand|Select|Wrap|Line Numbers
  1. <html>
  2. <head>
  3. <title>
  4. Search details Form
  5. </title>
  6. </head>
  7. <body>
  8. <form method = "POST" action = "search2.php">
  9. Dealer ID<input type = "text" id = "DealerId" name = "DealerId">
  10. <input type = "submit" name = "submit1" value = "Search1" >
  11. <?php
  12. if(isset($_POST['submit1']))
  13. {
  14. $name = $_POST['DealerId'];
  15. if($name != "")
  16. {
  17. mysql_connect("localhost", "root", "");
  18. mysql_select_db("rajesh");
  19. $sql = "select * from dealerlist where DealerID like '%".mysql_real_escape_string($name)."%'";
  20. $result = mysql_query($sql);
  21. $numRows = mysql_num_rows($result);
  22. if(empty($numRows))
  23. {
  24.     echo "Record are not exits";
  25. }
  26.  
  27. else{
  28. while($row = mysql_fetch_array($result))
  29. {
  30. ?>
  31. <table>
  32. <tr><td>Dealer ID<td><input type = "text" name = "Name" value = "<?php echo $row['DealerID']; ?>">
  33. <tr><td>Dealer Name<td><input type = "text" name = "Age" value = "<?php echo $row['DealerName']; ?>">
  34. <tr><td>Address<td><input type = "text" name = "Sex" value = "<?php echo $row['Street']; ?>"></tr>
  35. </table><br>
  36. ItemNo<input type = "text" name = "ItemNo">
  37. <input type = "submit" name = "submit2" value = "search2">
  38. <?php
  39. }
  40. }
  41. }
  42. }
  43. if(isset($_POST['submit2']))
  44. {
  45. $name1 = $_POST['ItemNo'];
  46. if($name1 != "")
  47. {
  48. mysql_connect("localhost", "root", "");
  49. mysql_select_db("rajesh");
  50. $sql1 = "select * from itemlist where ItemNO  like '%".mysql_real_escape_string($name1)."%'";
  51. $result1 = mysql_query($sql1);
  52. $numRows1 = mysql_num_rows($result1);
  53. if(empty($numRows1))
  54. {
  55.     echo "Record are not exits";
  56. }
  57. else{
  58. while($row1 = mysql_fetch_array($result1))
  59. {
  60. ?>
  61. <table>
  62. <tr><td>Item No<td><input type = "text" name = "ItemNo" value = "<?php echo $row1['ItemNo']; ?>">
  63. <tr><td>Item Name<td><input type = "text" name = "ItemName" value = "<?php echo $row1['ItemName']; ?>">
  64. </table>
  65. <?php
  66. }
  67. }
  68. }
  69. }
  70. ?>
  71.  
Jan 10 '13 #1
4 2405
Expand|Select|Wrap|Line Numbers
  1. <head>
  2. <title>
  3. Search details Form
  4. </title>
  5. </head>
  6. <body>
  7. <form method = "POST" action = "search2.php">
  8. Dealer ID<input type = "text" id = "DealerId" name = "DealerId">
  9. <input type = "submit" name = "submit1" value = "Search1" >
  10. <?php
  11. if(isset($_POST['submit1']))
  12. {
  13. $name = $_POST['DealerId'];
  14. if($name != "")
  15. {
  16. mysql_connect("localhost", "root", "");
  17. mysql_select_db("rajesh");
  18. $sql = "select * from dealerlist where DealerID like '%".mysql_real_escape_string($name)."%'";
  19. $result = mysql_query($sql);
  20. $numRows = mysql_num_rows($result);
  21. if(empty($numRows))
  22. {
  23.     echo "Record are not exits";
  24. }
  25.  
  26. else{
  27. while($row = mysql_fetch_array($result))
  28. {
  29. ?>
  30. <table>
  31. <tr><td>Dealer ID<td><input type = "text" name = "Name" value = "<?php echo $row['DealerID']; ?>">
  32. <tr><td>Dealer Name<td><input type = "text" name = "Age" value = "<?php echo $row['DealerName']; ?>">
  33. <tr><td>Address<td><input type = "text" name = "Sex" value = "<?php echo $row['Street']; ?>"></tr>
  34. </table><br>
  35. ItemNo<input type = "text" name = "ItemNo">
  36. <input type = "submit" name = "submit2" value = "search2">
  37. <?php
  38. }
  39. }
  40. }
  41. }
  42. if(isset($_POST['submit2']))
  43. {
  44. $name1 = $_POST['ItemNo'];
  45. if($name1 != "")
  46. {
  47. mysql_connect("localhost", "root", "");
  48. mysql_select_db("rajesh");
  49. $sql1 = "select * from itemlist where ItemNO  like '%".mysql_real_escape_string($name1)."%'";
  50. $result1 = mysql_query($sql1);
  51. $numRows1 = mysql_num_rows($result1);
  52. if(empty($numRows1))
  53. {
  54.     echo "Record are not exits";
  55. }
  56. else{
  57. while($row1 = mysql_fetch_array($result1))
  58. {
  59. ?>
  60. <table>
  61. <tr><td>Item No<td><input type = "text" name = "ItemNo" value = "<?php echo $row1['ItemNo']; ?>">
  62. <tr><td>Item Name<td><input type = "text" name = "ItemName" value = "<?php echo $row1['ItemName']; ?>">
  63. </table>
  64. <?php
  65. }
  66. }
  67. }
  68. }
  69. ?>
<html>
Jan 10 '13 #2
Rabbit
12,516 Expert Mod 8TB
If you want to run both, don't check to see which button was clicked.
Jan 11 '13 #3
First of all thanks mr.rabbit for responding to my question i have given u code and wts the problem pls follow of my code and reply once again .actually i want 2 buttons results to be there in page.
Jan 12 '13 #4
Rabbit
12,516 Expert Mod 8TB
Yes, I know. I answered your question.
Jan 13 '13 #5

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