how to get data from ajax responseText. Here i use three parts.

In first part
1.html..i have one combo box
and code as below

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<body>

<form name="ajax">

<select  onchange="request()" id="cmbnum">

<option value=1>ONE</option>

<option value=2>TWO</option>

<option value=3>THREE</option>

</select></form>

this java script part.i have function as below.
when i am using the syntax it return only empty alert....

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function request()

{

    optnum=document.getElementById("cmbnum").value;
 
    url="ajax\response.php?num="+optnum;
 
xmlhttp.onreadystatechange=function()

 {

   if(xmlhttp.readyState==4 && xmlhttp.status==200 )

     {
 
       ajaxres=xmlhttp.responseText;

    document.getElementById("sample").innerHTML=ajaxres;

    }

 }

xmlhttp.open("GET",url,true);

 xmlhttp.send();

}

this php part..

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if(isset($_REQUEST['num']))

{ 
 
    switch($_REQUEST['num'])

    {

        case 1:

        echo "ONE";

        break;

        case 2:

        echo "TWO";

        break;
 
    }
 
}

Apr 21 '12 #1

Subscribe Post Reply

3941

Dormilich

8,658

Expert Mod 8TB

where is the part where you define the XMLHttpRequest object?

Apr 22 '12 #2

harini0590

i include this as separate file named ajaxex.js in the function request()..

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try

{ 

    alert("hai");

    xmlhttp=new XMLHttpRequest();

}

catch(e)

{

    try

    {alert("hai");

     xmlhttp=new ActiveXObject("Msxml2.XMLHTTP");

    }

    catch(e)

    {

        try

        {alert("hai");

            xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");

        }

        catch(e)

        {

            xmlhttp=null;

            alert("ur browser is not work");

        }

    }

}

Apr 22 '12 #3

Dormilich

8,658

Expert Mod 8TB

i include this as separate file named ajaxex.js in the function request()

how do you do that exactly?

did you verify that all your variables/parameters are set correctly?

Apr 22 '12 #4

harini0590

by using the statement below i include the file in these file

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 <script language="javascript" type="text/javascript" src="ajaxex.js">

</script>

when i select anything from list box,suppose if it is one means it should display as ONE.When i simply give echo statement in php part it display back as alert message.but the code inside if statement is not work.so only i doesn't return anything to response text..
what i need to do now..

Apr 30 '12 #5

Dormilich

8,658

Expert Mod 8TB

do you have a live page?

Apr 30 '12 #6

harini0590

My coding is work.. with slight modification in php part and in <option> tag.

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<?php
 
    $sam=$_REQUEST['num'];
 
    switch($sam)

    {

        case "ONE":

        echo "ONE";

        break;

        case "TWO":

        echo "TWO";

        break;

        case "THREE":

        echo "THREE";

        break;
 
    }
 
?>
 
<form name="ajax">

<select  onchange="javascript:request()" id="cmbnum">

<option value="ONE">ONE</option>

<option value="TWO">TWO</option>

<option value="THREE">THREE</option>

</select>

here i get get alert when i select item in list box..
thanks for ur help..

Apr 30 '12 #7

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