WHats wrong with this code

[adam]

The folowing code produces an error althought i cant understand why it
does this can any one help? THANKS

ERROR = Notice: Undefined variable: tab in
C:\Inetpub\wwwroot\carpound\table\table1.php on line 32

<?php
$link = mysql_connect("localhost","root","admin") or
die(mysql_error());
mysql_select_db("car") or die (mysql_error());

$query = "SELECT
make,
modal,
reg
FROM
cars";

$result = mysql_query($query,$link) or die(mysql_error());
$num_movies = mysql_num_rows($result);

$head=<<<EOD
<h2><center>car</center></h2>
<table width='70%' border='1' cellpadding='2'
cellspacing='2' align='center'>
<tr>
<th>Car Make</th>
<th>Car Model</th>
<th>Car Reg number</th>
</tr>
EOD;

while($row = mysql_fetch_array($result))
{
$make = $row['make'];
$modal = $row['modal'];
$reg = $row['reg'];

$tab .=<<<EOD
<tr>
<td height=50>$make</td>
<td>$modal</td>
<td>$reg</td>
</tr>

EOD;
}

$tab .=<<<EOD
<tr>
<td> </td>
</tr>
<tr>
<td>Total :$num_movies Movies</td>
</tr>
EOD;
$bottom ="</table>";

$movie =<<<MOVIE
$head
$tab
$bottom
MOVIE;

print $movie;
?>

[Janwillem Borleffs]

adam wrote:

The folowing code produces an error althought i cant understand why it
does this can any one help? THANKS

ERROR = Notice: Undefined variable: tab in
C:\Inetpub\wwwroot\carpound\table\table1.php on line 32

Just like the error indicates: you failed to initialize the $tab variable
before using it.

To fix this, just put $tab = ''; at the top of your page.
JW

[Alan Little]

Carved in mystic runes upon the very living rock, the last words of
Janwillem Borleffs of comp.lang.php make plain:

adam wrote:

The folowing code produces an error althought i cant understand why
it does this can any one help? THANKS

ERROR = Notice: Undefined variable: tab in
C:\Inetpub\wwwroot\carpound\table\table1.php on line 32

Just like the error indicates: you failed to initialize the $tab
variable before using it.

To fix this, just put $tab = ''; at the top of your page.

Or turn off notice-level messages.

--
Alan Little
Phorm PHP Form Processor
http://www.phorm.com/

[Janwillem Borleffs]

Alan Little wrote:

Or turn off notice-level messages.

Nope. Application should be able to run anywhere without specific ini
settings to keep them portable.

Especially when developing, error_reporting should be set to strictest level
(E_ALL).
JW

[Mark]

adam wrote:

The folowing code produces an error althought i cant understand why it
does this can any one help? THANKS

ERROR = Notice: Undefined variable: tab in
C:\Inetpub\wwwroot\carpound\table\table1.php on line 32

....
...
.. $tab .=<<<EOD ....
...
..
$tab .=<<<EOD

$tab .= xxxx

is the same as writing

$tab = $tab . xxxx

thus, PHP is looking for previous declarations/definitions of the variable
$tab, and not finding any.

it is probably a good idea to just initialise it earlier:

$tab = '';

or some such thing.

mark.


--
I am not an ANGRY man. Remove the rage from my email to reply.

[Michael Fesser]

.oO(Alan Little)

Or turn off notice-level messages.

Not on a development system. Good code is notice-free.

Micha

[Amit]

Hi

Because in yr 'php.ini' file error_reporting directive is set to show
'Notice Info' from php parser.

To debug replace this "$tab .=<<<EOD" with "$tab =<<<EOD"
Note: just remove concatenate operator.

Amits

Thanks